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Evgesh-ka [11]
3 years ago
14

PLEASE HELP!!

Chemistry
1 answer:
jeka57 [31]3 years ago
3 0
I think it is C. i took a quiz on that.
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You see a worm crawling along the ground and wonder if scientists consider it living or nonliving. Which item below would not be
lisov135 [29]

Answer: a. A worm can move so it must be living.

Explanation:

If a worm is moving it is classified as a moving worm also known to be living if moving.

A worm could reproduce therefore it is living.

Worms do pass dirt into and through there bodies to eat of the minerals and discarding things through and let out.

If you do cut a worm in half it may damage it but since it has basically two heads on girl one boy and cut in half it may split them up, and make damage but they will eventually grow back if the injuries are not severe.

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3 years ago
Used in kitchen utensils. <br><br>what is this MNMULUAI​
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Answer:

the best person to whom it may be able or chulbul the same day of Ch-2 Ch-4 book exercise in a great day and I will join you for your voice is not coming to the same day

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3 years ago
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How would you quickly determine whether a cleaning
Leona [35]

Answer:

The answer is explained below

Explanation:

If you add dilute HCl (Hydrochloric Acid) to the solution, and you see fizzing, then it is the carbonate. I would recommend doing this under a fume hood, as HCl has a wicked smell, and can make a few people sick to their stomach (however, you probably won't be using 12M concentrated HCl)

7 0
3 years ago
The attachment below is the question:
irakobra [83]

Answer:

gold

Explanation:

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7 0
3 years ago
The elementary reaction 2H2O(g)↽−−⇀2H2(g)+O2(g) 2H2O(g)↽−−⇀2H2(g)+O2(g) proceeds at a certain temperature until the partial pres
Dima020 [189]

Answer:

6.25\times 10^{-6} is the value of the equilibrium constant at this temperature.

Explanation:

Equilibrium constant in terms of partial pressure is defined as the ratio of partial pressures of products to the partial pressures  of reactants each raised to the power equal to their stoichiometric ratios. It is expressed as K_{p}

2H_2O(g)\rightleftharpoons 2H_2(g)+O_2(g)

Partial pressures at equilibrium:

p^o_{H_2O}=0.070 atm

p^o_{H_2}=0.0035 atm

p^o_{O_2}=0.0025 atm

The equilibrium constant in terms of pressures is given as:

K_p=\frac{(p^o_{H_2})^2\times (p^o_{O_2})}{(p^o_{H_2O})62}

K_p=\frac{(0.0035 atm)^2\times 0.0025 atm}{(0.070 atm)^2}=6.25\times 10^{-6}

6.25\times 10^{-6} is the value of the equilibrium constant at this temperature.

5 0
3 years ago
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