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puteri [66]
2 years ago
7

Horizontal pieces can be produced at a rate of 200 per labor hour. a carpenter uses 500 horizontal pieces and 22 vertical pieces

while making racks for an hour. you have 900 horizontal pieces and 50 vertical pieces in stock right now. for the next hour, you assign juan to rack making, debbie to trim making, and both mike and stan to horizontal piece production. please answer the following two questions, based on this information and assuming that nothing would interfere with or otherwise influence the activity described.
1. at the end of the next hour, how many vertical pieces will be available in stock? a) 28 vertical pieces b) 48 vertical pieces c) 78 vertical pieces d) 50 vertical pieces e) 100 vertical pieces
2. at the end of the next hour, how many horizontal pieces will be available in stock? a) 450 horizontal pieces b) 600 horizontal pieces c) 800 horizontal pieces d) 1,150 horizontal pieces e) 1,300 horizontal piec
Mathematics
1 answer:
ira [324]2 years ago
7 0
  1. The number of vertical pieces will be 28. Then the correct option is A.
  2. The number of horizontal pieces will be 600. Then the correct option is B.
<h3>What is decision-making?</h3>

The process of making choice is by identifying the correct decision, gathering information, and assessing alternative solutions.

Horizontal pieces can be produced at a rate of 200 per labor hour.

A carpenter uses 500 horizontal pieces and 22 vertical pieces while making racks for an hour.

You have 900 horizontal pieces and 50 vertical pieces in stock right now.

For the next hour, you assign Juan to rack making, Debbie to trim making, and both mike and stan to horizontal piece production.

1.  Then at the end of the next hour, the number of vertical pieces available in stock will be

→ 50 - 22

→ 28

Thus, the number of verticle pieces will be 28.

2.  Then at the end of the next hour, then the number of horizontal pieces available in stock will be

→ 900 + 200 - 500

→ 600

More about the decision-making link is given below.

brainly.com/question/3369578

#SPJ1

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emmainna [20.7K]

The x- and y- coordinates of point P on the directed line segment from K to J such that P is Three-fifths the length of the line segment from K to J is  (85, 105).

Given

On a coordinate plane, a line is drawn from point K to point J. Point K is at (160, 120) and point J is at (negative 40, 80).

<h3>Coordinates</h3>

The coordinates point any point can be found by using the following formula.

\rm X=\dfrac{m}{m+n}(x_2-x_1)+x_1\\\\ Y=\dfrac{m}{m+n}(y_2-y_1)+y_1

The x- and y- coordinates of point P on the directed line segment from K to J such that P is Three-fifths the length of the line segment from K to J is;

\rm X=\dfrac{m}{m+n}(x_2-x_1)+x_1\\\\ X = \dfrac{3}{3+5}(-40-160)+160\\\\ X = 3 \times (-25)+160\\\\\X = -75+160\\\\ X = 85\\\\\ Y=\dfrac{m}{m+n}(y_2-y_1)+y_1\\\\ Y=\dfrac{3}{3+5}(80-120)+120\\\\Y =- 3\times 5 +`120\\\\Y=-15+120\\\\Y=105

Hence, the x- and y- coordinates of point P on the directed line segment from K to J such that P is Three-fifths the length of the line segment from K to J is  (85, 105).

To know more about co-ordinates click the link given below.

brainly.com/question/13847533

5 0
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20a + 158 +6c = 20 (6) + 15 (4) + 6(8)<br> +<br> ?<br> +<br> ?
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Step-by-step explanation:

20a + 158+6c=you will expand the brackets

= so it is 120+60+48

20a+158+6c=120+60+48

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Answer:

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Step-by-step explanation:

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ycow [4]

With an equation you must isolate x or whatever the variable is. Operations are the things used to make the difference like +,-,x,/.

A great example of this is the following

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First add 12 to both sides making the equation go to

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