The first five terms of a sequence are

Mathematics

1 answer:

Elena L [17]2 years ago

5 0

Answer:

(a) 7 + 3( n - 1 )

(b) 1006

Step-by-step explanation:

ARITHMETIC SEQUENCE.

The number of term of an Arithmetic progression has the formular :

nth term = a + ( n - 1 ) d

a = 7

d = 10 - 7 = 3

nth term = 7 + ( n - 1 ) 3

= 7 + 3n - 3

= 7 + 3( n - 1 )

Therefore,

the nth term of the sequence

= 7 + 3( n - 1 )

(b) For the 1000th term

= 7 + 3 ( 1000-1 )

= 7 + ( 999 )

7 + 999 = 1006

Therefore,

the 1000th term = 1006

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6-7(x+1)= -3(2-x)<br> How do you solve this?

kicyunya [14]

<h3><u>Explanation</u></h3>

Given the equation.

$6 - 7(x + 1) = - 3(2 - x)$

Distribute/Simplify

$6 - 7x - 7 = - 6 + 3x \\ - 1 - 7x = - 6 + 3x$

Solve the equation for x-term by making x as the subject.

$- 1 + 6 = 7x + 3x \\ 5 = 10x \\ \frac{5}{10} = x \\ \frac{1}{2} = x$

Answer Check by substituting the value of x in the equation.

$6 - 7( \frac{1}{2} ) - 7 = - 6 + 3( \frac{1}{2} ) \\ 6 - \frac{7}{2} - 7 = - 6 + \frac{3}{2} \Longrightarrow \sf{You \: \: can \: \: change \: \: sides \: \: to \: \: make \: \: it \: \: easier} \\ 6 - 7 + 6 = \frac{7}{2} + \frac{3}{2} \\ 5 = \frac{10}{2} \\ 5 = 5 \: \green{ \checkmark}$