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Contact [7]
2 years ago
12

The first five terms of a sequence are

Mathematics
1 answer:
Elena L [17]2 years ago
5 0

Answer:

(a) 7 + 3( n - 1 )

(b) 1006

Step-by-step explanation:

ARITHMETIC SEQUENCE.

The number of term of an Arithmetic progression has the formular :

nth term = a + ( n - 1 ) d

a = 7

d = 10 - 7 = 3

nth term = 7 + ( n - 1 ) 3

= 7 + 3n - 3

= 7 + 3( n - 1 )

Therefore,

the nth term of the sequence

= 7 + 3( n - 1 )

(b) For the 1000th term

= 7 + 3 ( 1000-1 )

= 7 + ( 999 )

7 + 999 = 1006

Therefore,

the 1000th term = 1006

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Solve the following equation for y<br> 1/2x+y=24<br> what is y?
Basile [38]

Answer:

y=-1/2x+24

Step-by-step explanation:

you solve for y by isolating the y on one side of the equation and the rest of the equation on the opposite side of the equal sign.

1/2x-1/2x+y=24-1/2x

y=24-1/2x

rewritten: y=-1/2x+24

5 0
3 years ago
What is the value of x in the equation 3(2x+8)=0
maxonik [38]

Answer:

x = -4

Step-by-step explanation:

3(2x+8)=0

Divide each side by 3

3/3(2x+8)=0/3

2x+8 = 0

Subtract 8 from each side

2x+8-8=0-8

2x = -8

Divide by 2

2x/2 = -8/2

x = -4

7 0
3 years ago
Anita invested $6000, some at 5% and the rest at 6%. If the yearly income is $337.50, what is the amount invested at each rate?
Pepsi [2]

Let the amount invested with 5% interest be x

Therefore, the amount invested with 6% interest will be (6000-x)

It is given that the total interest earned yearly is $337.5. Thus, the equation of interest will be:

\frac{5}{100}x+\frac{6}{100}(6000-x)=337.5

Multiplying both sides by 100 we get:

5x+6(6000-x)=33750

5x+36000-6x=33750

Subtracting both sides by 36000 we get:

-x=-2250

\therefore x=2250

Thus, the amount invested at 5% is $2250

Therefore, the amount invested at 6% will be $(6000-2250)=$3750

6 0
3 years ago
A credit union loaned out $50,000, part at an annual rate of 6% and the rest at an annual rate of 12% . The collected combined i
Natasha_Volkova [10]

Answer: the credit union loaned out $40000 at 6% and $10000 at 12%

Step-by-step explanation:

Let x represent the amount that the

credit union loaned out at the annual rate of 6%.

Let y represent the amount that the

credit union loaned out at the annual rate of 12%.

credit union loaned out $50,000, part at an annual rate of 6% and the rest at an annual rate of 12%. It means that

x + y = 50000

The interest on $x after 1 year would be

6/100 × x = 0.06x

The interest on $y after 1 year would be

12/100 × y = 0.12y

The collected combined interest was $3,600 that year. It means that

0.06x + 0.12y = 3600- - - - - - - - - 1

Substituting x = 50000 - y into equation 1, it becomes

0.06(50000 - y) + 0.12y = 3600

3000 - 0.06y + 0.12y = 3600

- 0.06y + 0.12y = 3600 - 3000

0.06y = 600

y = 600/0.06

y = $10000

x = 50000 - y = 50000 - 10000

x = $40000

5 0
3 years ago
What are the numbers that are divisible by three
faust18 [17]
The numbers divisible by 3 are multiples of 3.
6 0
3 years ago
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