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3 years ago

I need help please I will mark you brainlists

Mathematics

1 answer:

V125BC [204]3 years ago

6 0

Answer:

2. ΔABC is isosceles

Step-by-step explanation:

Given : m∠A = 50

m∠BCD = 180 - (m∠BDC + m∠DBC)

= 180 - (100 + 30)

= 50

then

m∠A = m∠BCD

therefore ΔABC is isosceles

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Which statement describes the function y = axn when a = 1 and n is odd?

kiruha [24]

Answer:

The graph is symmetric about the origin.

The graph does not pass through the origin.

Step-by-step explanation:

We're given:

the function y=axn
a = 1
n is odd

Because a = 1, then the given function can be rewritten as y = n.

The graph opens down

The function y = n will produce a horizontal line. Any function in the form of y = a single number, such as 4 or 9.3 will produce a horizontal line.

The graph is symmetric about the origin.

This is true, given the graph is a horizontal line.

The graph does not pass through the origin.

This is also true. We're given that n is an odd number. The graph will only pass through the origin if n = 0, and 0 is even.

The graph has more than one x-intercept.

This would only be true when n = 0, and this isn't possible. So, no.

4 0

2 years ago

Read 2 more answers

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algol13

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3 years ago

What is the length of the curve with parametric equations x = t - cos(t), y = 1 - sin(t) from t = 0 to t = π? (5 points)

zzz [600]

Answer:

B) 4√2

General Formulas and Concepts:

Calculus

Differentiation

Derivatives
Derivative Notation

Basic Power Rule:

f(x) = cxⁿ
f’(x) = c·nxⁿ⁻¹

Parametric Differentiation

Integration

Integrals
Definite Integrals
Integration Constant C

Arc Length Formula [Parametric]: $\displaystyle AL = \int\limits^b_a {\sqrt{[x'(t)]^2 + [y(t)]^2}} \, dx$

Step-by-step explanation:

Step 1: Define

Identify

$\displaystyle \left \{ {{x = t - cos(t)} \atop {y = 1 - sin(t)}} \right.$

Interval [0, π]

Step 2: Find Arc Length

[Parametrics] Differentiate [Basic Power Rule, Trig Differentiation]: $\displaystyle \left \{ {{x' = 1 + sin(t)} \atop {y' = -cos(t)}} \right.$
Substitute in variables [Arc Length Formula - Parametric]: $\displaystyle AL = \int\limits^{\pi}_0 {\sqrt{[1 + sin(t)]^2 + [-cos(t)]^2}} \, dx$
[Integrand] Simplify: $\displaystyle AL = \int\limits^{\pi}_0 {\sqrt{2[sin(x) + 1]} \, dx$
[Integral] Evaluate: $\displaystyle AL = \int\limits^{\pi}_0 {\sqrt{2[sin(x) + 1]} \, dx = 4\sqrt{2}$