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lidiya [134]
2 years ago
13

Solve:i)x+y=5ii)x-y=3iii)2x+y=7iv)3x-2y=0​

Mathematics
1 answer:
Ulleksa [173]2 years ago
5 0

Answer:

I) X+Y

when X=0

0+y=5

Y=5

When Y=0

X+0=5

X=5

(X,y)=(5,5)

(ii) X-Y=3

When X=0

0-Y=3

Y=-3

When Y=0

X-0=3

X=3

(X,Y)=(3,3(

(III) 2x+Y=7

when X=0

0+Y=7

Y=7

when Y=0

2x+0=7

2x=7

X=7/2 or 3.5

(X,Y)=(3.5,7)

(Iv)

3X-2Y=0

when X=0

0-2Y=0

-2Y=0

Y=0

When Y=0

3x-0=0

3X=0

X=0

(X,Y)=(0,0)

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Step-by-step explanation:

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Step-by-step explanation:

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We know this because, if we reorganize the equation into the standard form  y = mx + b, we get y = -(x²) + 1. This means that for any value we substitute for x, y will always be negative. The answer is B.

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We set the equation equal to zero like this:

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IRINA_888 [86]

Answer:

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Step-by-step explanation:

6 0
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