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I am Lyosha [343]
3 years ago
9

Solve: |2 + 4x| 11

Mathematics
1 answer:
erastovalidia [21]3 years ago
5 0

Correct option is A) [-13/4, 9/4] .

<u>Step-by-step explanation:</u>

Here we have following equation as  |2 + 4x| = 11 or , |2 + 4x| = 11 . We need to solve for the value of x .Let's find out:

We know that Modulus Function is both positive & negative for particular values of x , i.e.

|2 + 4x| is positive :

⇒ |2+4x|=11

⇒  2+4x=11

⇒  4x=9

⇒  x = \frac{9}{4}

|2 + 4x| is negative :

⇒ |2+4x|=11

⇒  -2-4x=11

⇒  -4x=13

⇒  x = \frac{-13}{4}

Therefore , Correct option is A) [-13/4, 9/4] .

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Step-by-step explanation:

Choosing 4 digits out of 10 = 10C4 = 210.

Arranging the 4 digits in 4 places = 4!

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= 325 * 2! = 650.

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What is the sum of the infinite geometric series?<br><br> 120 + 20+ 10/3 + 5/9+...
Sergeu [11.5K]

Answer:

for an infinite geometric series the formula for the sum of the infinite geometric series when the common ratio is less than one is given by

\frac{a_{1} }{1 - r} = \frac{120}{1 - \frac{1}{6} } = \frac{120}{\frac{5}{6} } = \frac{120 \times 6}{5} = 144.

Step-by-step explanation:

i) from the given series we can see that the first term is a_{1 } = 120.

ii) let the common ratio be r.

iii) the second term is 20 = 120 × r

   therefore r = 20 ÷ 120 = \dfrac{1}{6}

iv) the third term is \frac{10}{3} = 20 × r

    therefore r = \dfrac{10}{3} ÷ 20 = \dfrac{1}{6}

v) for an infinite geometric series the formula for the sum of the infinite geometric series when the common ratio is less than one is given by

\frac{a_{1} }{1 - r} = \frac{120}{1 - \frac{1}{6} } = \frac{120}{\frac{5}{6} } = \frac{120 \times 6}{5} = 144.

6 0
3 years ago
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