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GREYUIT [131]
3 years ago
5

Someone please help me solve this lol

Mathematics
1 answer:
dlinn [17]3 years ago
5 0

Answer:

obtuse acute

Step-by-step explanation:

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Carlos has taken an initial dose of a prescription medication.
Marat540 [252]

Answer:

3.48 hours

Step-by-step explanation:

The equation is:

M(t)=20 e^{-0.86t}

Where

M(t) is the amount of medication remaining in mg

t is the time it takes, in hours

The questions asks HOW LONG it will take to make the remaining medication to 1 milligrams (1 mg)??

We have to substitute M(t) with "1" and find the corresponding value of "t". We will use natural log to solve this. Shown below:

M(t)=20e^{-0.86t}\\1=20e^{-0.86t}\\0.05=e^{-0.86t}\\Ln(0.05)=Ln(e^{-0.86t})\\Ln(0.05)=(-0.86t)Ln(e)\\t=\frac{Ln(0.05)}{-0.86}\\t=3.48

<u>Note: </u> Ln(e) = 1

This means, the amount of time it will take is about 3.48 hours

8 0
3 years ago
How many vertice has a hexagonal <br><br>pyramid​
adelina 88 [10]

Answer: 7

Step-by-step explanation:

6 0
1 year ago
Find the volume of the cone. Use 3.14 for n. Round to the nearest tenth.
enyata [817]

Answer:

1590.6cm {}^{3}

Step-by-step explanation:

volume \: of \: a \: cone \: v =  \frac{1}{3}\pi \: r {}^{2} h \\ radius =  \frac{diameter}{2}  =  \frac{15}{2}  = 7.5 \\ v =  \frac{1}{3}  \times 3.42 \times (7.5) {}^{2} \times 27 \\ v =  \frac{3.142 \times 7.5 \times 7.5 \times 27}{3}    \\ v =  \frac{4771.9125}{3}  = 1590.6375 \\ v = 1590.6cm {}^{3} (approximatly) \\ please \: rate \: and \: mark \: brainliest

7 0
2 years ago
Add the numbers from 1 to 100 by following the same steps you used in 1.
oksano4ka [1.4K]
Summaation of a sequence

or see a smaller scale
from 1 to 10
notice
1+10=11
2+9=11
etc
5+6=11
10/2=5
there are 5 pairs
5*11=55

so

1 to 100
1+100=101
2+99=101
...
50+51=101

100/2=50
there ar 50 pairs
50 times 101=5050

the sum is 5050
3 0
3 years ago
Jacob earns £93.20 for 8 hours work. he gets the same amount of pay for each hour. what is his rate of pay per hour?
photoshop1234 [79]
The answer is 11.65!
5 0
3 years ago
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