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3 years ago

15

Gabe filled 5 glasses of the same size with ice tea from a full 64-ounce pitcher. There were 3 ounces left in the pitcher. Which

equation and solution give the number of ounces, s, in each glass?

2 answers:

Helga [31]3 years ago

6 0

Answer:

The number of ounces in each glass is $12.2\ ounces$

Step-by-step explanation:

Let

s-------> the number of ounces in each glass

we know that

To get the number of ounces in each glass, subtract the amount of tea left in the pitcher from the total amount of tea and divide the result by the number of glasses.

so

The equation that represent the situation is

$s=(64-3)/5$

$s=(61)/5=12.2\ ounces$

dolphi86 [110]3 years ago

3 0

Answer:

Step-by-step explanation:

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A human resource manager wants to see if there is a difference in the proportion of minority applicants who get the job and the

mash [69]

Answer:

Error Bound = 0.04

Step-by-step explanation:

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With that in mind, the objective of a confidence interval is to give us a better insight of where we expect to find the "true" value of the parameter with a certain degree of certainty.

The estivamative of the true difference between proportions was -0.19 and the confidence interval was [-0.23 ; -0.15].

The question also defines the error bound, as the right endpoint of the confidence interval minus the sample mean difference, so it's pretty straight foward:

Error Bound = $-0.15 -(-0.19) = -0.15 + 0.19 = 0.04$

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3 years ago

3(у +8) - 10<br> Distribute property

cupoosta [38]

Answer:

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Step-by-step explanation:

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3 years ago

1. The area of a circle is 60 square units. What is the area of ...

AVprozaik [17]

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1 year ago

98 POINTS The total cost of a boat rental includes the price per hour plus the cost of one full tank of gas. The table below rep

Jet001 [13]

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2 years ago

I need help writing the first 5 terms of the sequence!

Angelina_Jolie [31]

The first five terms of the sequence are 1, 4, 7, 10, 13.

Solution:

Given data:

$a_{1}=1$

$a_{n}=a_{n-1}+3$

General term of the arithmetic sequence.

$a_{n}=a_{n-1}+d$ , where d is the common difference.

d = 3

$a_{n}=a_{n-1}+3$

Put n = 2 in $a_{n}=a_{n-1}+3$ , we get

$a_{2}=a_1+3$

$a_{2}=1+3$

$a_2=4$

Put n = 3 in $a_{n}=a_{n-1}+3$ , we get

$a_{3}=a_2+3$

$a_{3}=4+3$

$a_3=7$

Put n = 4 in $a_{n}=a_{n-1}+3$ , we get

$a_{4}=a_3+3$

$a_{4}=7+3$

$a_4=10$

Put n = 5 in $a_{n}=a_{n-1}+3$ , we get

$a_{5}=a_4+3$

$a_{5}=10+3$

$a_5=13$

The first five terms of the sequence are 1, 4, 7, 10, 13.

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3 years ago