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3 years ago

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Lengths of newborn girls are normally distributed with a mean of 49.2 cm and a standard deviation of 1.8 centimeters. Consider a

group of 2000 newborn girls. How many girls will be 51 centimeters or shorter?

1 answer:

Elza [17]3 years ago

3 0

The answer is <span>1683.

Hope this helps.</span>

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John builds a square dog pen that has an area of 81 square feet. He then builds a

Fiesta28 [93]

Answer:

21.0%

Step-by-step explanation:

8 0

3 years ago

For which method of data collection is it most important to select a representative sample so that the information may be genera

dalvyx [7]

ANSWER:

INFERENTIAL STATISTICS

STEP-STEP-BY EXPLANATION:

Inferential statistics are mathematical tools for estimating how likely it is that a statistical result based on data from a random sample is representative of the population from which the sample is assumed to have been selected.

It can make inferences from data to more general conditions like

* estimate the degree of confidence that can be placed in generalizations from a sample to the population from which the sample was drawn. (generalize your sample to a larger population)

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3 years ago

Based on historical data in Oxnard college, we believe that 37% of freshmen do not visit their counselors regularly. For this ye

slega [8]

Answer:

A sample size of 1031 is required.

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of $\pi$ , and a confidence level of $1-\alpha$ , we have the following confidence interval of proportions.

$\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}$

In which

z is the zscore that has a pvalue of $1 - \frac{\alpha}{2}$ .

The margin of error is of:

$M = z\sqrt{\frac{\pi(1-\pi)}{n}}$

37% of freshmen do not visit their counselors regularly.

This means that $\pi = 0.37$

98% confidence level

So $\alpha = 0.02$ , z is the value of Z that has a pvalue of $1 - \frac{0.02}{2} = 0.99$ , so $Z = 2.327$ .

You would like to be 98% confident that your estimate is within 3.5% of the true population proportion. How large of a sample size is required?

A sample size of n is required.

n is found when M = 0.035. So

$M = z\sqrt{\frac{\pi(1-\pi)}{n}}$

$0.035 = 2.327\sqrt{\frac{0.37*0.63}{n}}$

$0.035\sqrt{n} = 2.327\sqrt{0.37*0.63}$

$\sqrt{n} = \frac{2.327\sqrt{0.37*0.63}}{0.035}$

$(\sqrt{n})^2 = (\frac{2.327\sqrt{0.37*0.63}}{0.035})^2$

$n = 1030.4$

Rounding up:

A sample size of 1031 is required.

4 0

3 years ago

Two numbers that multiply to -100 and add to 15

Whitepunk [10]

Answer:

-5 and 20

Step-by-step explanation:

-5 + 20 = 15

-5 * 20 = -100

3 0

3 years ago

-⅕ (10-5+25x)<br> Please help!

Yanka [14]

Answer:

- $-\frac{1}{5} * (5+25x)\\-\frac{1}{5} *5-\frac{1}{5}(25x)\\-1-\frac{1}{5}(25x)\\-1 -1 (5x)\\01-5x$

Step-by-step explanation:

7 0

3 years ago