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Ipatiy [6.2K]
2 years ago
10

If the solution to a linear system of equations is x=6 and y= 2 and you graphed the two equations, where would the two lines int

ersect? How do you know?
Mathematics
1 answer:
coldgirl [10]2 years ago
8 0
<h3>The lines intersect at (x,y) = (6,2)</h3>

This is simply because the x coordinate is 6 and the y coordinate is 2.

The line x = 6 is a vertical line in which all points on it have an x coordinate of 6. It goes through 6 on the x axis.

The line y = 2 is horizontal where all points on it have a y coordinate of 2.

The vertical and horizontal lines intersect at (6,2)

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Sally has just finished her thirty-fifth year with her company and is getting ready to retire. During her thirty-five years, Sal
olya-2409 [2.1K]

The <em>correct answer</em> is:

$19,153.26.

Explanation:

She will receive 42% of her average annual salary. This salary was $45,603.

To find 42% of a number, we first convert the percent to a decimal: 42% = 42/100 = 0.42.

Next we multiply this by the number we're taking the percent of:

0.42(45603) = 19153.26.

7 0
3 years ago
Read 2 more answers
Which situation CANNOT be represented by this equation? 6−7=29?
lakkis [162]

Answer:

The answer is Joel earns $7 per hour to mow his aunt’s lawn. If he spends $6 on gas, how many hours, x, will he need to mow to have $29 left?

Step-by-step explanation:

5 0
3 years ago
At the hardware store, you purchased a box of nails for 17 dollar. You had a coupon that took off 20% from the nails. Sales tax
Vikentia [17]
(17-.2(17))+(17+.06(17))

5 0
3 years ago
Read 2 more answers
Generate a number that has a digit in the hundred thousand place that is 10 times the digit in the ten thousands place.
baherus [9]

Answer:

1000000

ten thousands place : 0

hundred thousands place : 10 x 0 = 0

3 0
3 years ago
ZE is the angle bisector of measure YEX and the perpendicular bisector of GF, GX is the angle bisector of measure YGZ and the pe
den301095 [7]

Answer:

C

Step-by-step explanation:

The center of inscribed circle into triangle is point of intersection of all interior angles of triangle.

The center of circumscribed circle over triabgle is point of intersection of perpendicular bisectors to the sides.

Circumscribed circle always passes through the vertices of the triangle.

Inscribed circle is always tangent to the triangle's sides.

In your case angles' bisectors and perpendicular bisectors intesect at one point, so point A is the center of inscribed circle and the center of corcumsribed circle. Thus, these circles pass through the points X, Y, Z and G, E, F, respectively.

7 0
3 years ago
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