The equation of a hyperbola is:
(x – h)^2 / a^2 - (y – k)^2 / b^2 = 1
So what we have to do is to look for the values of the variables:
<span>For the given hyperbola : center (h, k) = (0, 0)
a = 3(distance from center to vertices)
a^2 = 9</span>
<span>
c = 7 (distance from center to vertices; given from the foci)
c^2 = 49</span>
<span>By the hypotenuse formula:
c^2 = a^2 + b^2
b^2 = c^2 - a^2 </span>
<span>b^2 = 49 – 9</span>
<span>b^2 = 40
</span>
Therefore the equation of the hyperbola is:
<span>(x^2 / 9) – (y^2 / 40) = 1</span>
First you’ll multiply to get 3x2x2 + 4x3. Then add them together. 12+12=24
Answer:
Step-by-step explanation:
(-6+12i)-(7-19i)=
-6+12i-7+19i=
-13+31i
(b)
Answer:
area= 1/2 × d1 ×d2
d = diagonal
area= 1/2 ×24×18 =216 unit^2
Answer:
33 1/3 lb
Step-by-step explanation:
When the distance between them goes from 8 ft to 12 ft, it is 1.5 times what it was. Then the force will be multiplied by the inverse of the square of this:
(75 lb)×1/(1.5²) = 75/2.25 lb = 33 1/3 lb
At 12 feet apart, the attraction force is 33 1/3 pounds.