Ask question

Ask question

All categories

3 years ago

13

Factorise x^2 + 7x -30

2 answers:

kumpel [21]3 years ago

7 0

The answer is
(x+10)(x-3)

maks197457 [2]3 years ago

3 0

$x^{2} + 7x - 30 \\ \\ (x - 3)(x + 10) \\ \\ Answer: \fbox {(x - 3)(x + 10)}$

You might be interested in

What is the width of a rectangle that has an area of 96 square inches and a length of 12 inches?

tatiyna

Answer:

width = 8

Step-by-step explanation:

to find the width of a rectangle you need to to the equation w= A ÷ l. when you put in the numbers you gets w = 96 ÷ 12.

96 ÷ 12 = 8 so w = 8

7 0

3 years ago

The area of the base of a square notepad is 2.25 square inches. What is the length of one side of the base of the notepad?

scoundrel [369]

Answer:

1.5 inches

Step-by-step explanation:

Because the base of the notepad is a square, that means that each side of the base would be equal. Since the area is 2.25 square inches, and each side would have to be equal, the equation to solve would be x*x = 2.25, or x^2=2.25. So, you just take the square root of both sides, and x=1.5 inches. Each side of the notepad would be 1.5 inches.

4 0

3 years ago

Polygon ABCDE ~ Polygon FGHIJ<br> What is the scale factor of polygon ABCDE to polygon FGHIJ?

Nataly [62]

Answer:

A. $\frac{1}{3}$

Step-by-step explanation:

I'm not sure if this is right

5 0

3 years ago

Plzzz help me with this I’ll give brainliest

scoray [572]

Answer18:

The quadrilateral ABCD is not a parallelogram

Answer19:

The quadrilateral ABCD is a parallelogram

Step-by-step explanation:

For question 18:

Given that vertices of a quadrilateral are A(-4,-1), B(-4,6), C(2,6) and D(2,-4)

The slope of a line is given m= $\frac{Y2-Y1}{X2-X1}$

Now,

The slope of a line AB:

m= $\frac{Y2-Y1}{X2-X1}$

m= $\frac{6-(-1)}{(-4)-(-4)}$

m= $\frac{7}{0}$

The slope is 90 degree

The slope of a line BC:

m= $\frac{Y2-Y1}{X2-X1}$

m= $\frac{6-6}{(-4)-(-1)}$

m= $\frac{0}{(-3)}$

The slope is zero degree

The slope of a line CD:

m= $\frac{Y2-Y1}{X2-X1}$

m= $\frac{(-4)-6}{2-2}$

m= $\frac{-10}{0}$

The slope is 90 degree

The slope of a line DA:

m= $\frac{Y2-Y1}{X2-X1}$

m= $\frac{(-1)-(-4)}{(-4)-(2)}$

m= $\frac{3}{-6}$

m= $\frac{-1}{2}$

The slope of the only line AB and CD are the same.

Thus, The quadrilateral ABCD is not a parallelogram

For question 19:

Given that vertices of a quadrilateral are A(-2,3), B(3,2), C(2,-1) and D(-3,0)

The slope of a line is given m= $\frac{Y2-Y1}{X2-X1}$

Now,

The slope of a line AB:

m= $\frac{Y2-Y1}{X2-X1}$

m= $\frac{2-3}{3-(-2)}$

m= $\frac{-1}{5}$

The slope of a line BC:

m= $\frac{Y2-Y1}{X2-X1}$

m= $\frac{(-1)-2}{2-3}$

m= $\frac{-3}{-1}$

m=3

The slope of a line CD:

m= $\frac{Y2-Y1}{X2-X1}$

m= $\frac{0-(-1)}{(-3)-2}$

m= $\frac{-1}{5}$

The slope of a line DA:

m= $\frac{Y2-Y1}{X2-X1}$

m= $\frac{3-0}{(-2)-(-3)}$

m=3

The slope of the line AB and CD are the same

The slope of the line BC and DA are the same

Thus, The quadrilateral ABCD is a parallelogram

3 0

3 years ago

What’s the answer to this problem?

kolbaska11 [484]

Hello :))

82 x 12 = 984

Hope this helps!

7 0

3 years ago

Read 2 more answers