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3 years ago

Find a quadratic equation with integer coefficients that has the following solution set of {4,4/5}

Mathematics

1 answer:

schepotkina [342]3 years ago

4 0

(x-4)(x-4/5)

Hope this helped!

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Which ordered pairs are solutions to the inequality 2x-y>1?

RideAnS [48]

Answer:

Any points in the shaded region including (2,-2) and (-3,-8)

Step-by-step explanation:

Convert the line into slope intercept form and graph it.

2x-y > 1 becomes -y>1-2x. Divide both sides by -1 and you get y<2x-1. Graph it with the shaded area on the right and a dashed line.

Any point which falls within the shaded red of the graph is a solution. No points on the line since it is not equal to (its dashed) are solutions. Check the location of your points to verify that they fall within this area.

(-3, -8) ---Yes

(-1, -3) ---No

(0, 5) --- No

(1, 6) --- No

(2, -2) ---Yes

8 0

3 years ago

Mrs. Martinez has a bowl of candy that she passes out to trick-or-treaters. A group of 5 children dressed in costumes comes to h

Kisachek [45]

Answer:

Step-by-step explanation:

5x3=15

7 0

2 years ago

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John takes out a personal loan for $5,000 at an annual interest rate 7.5%, compounded monthly. He plans to pay off the loan (inc

myrzilka [38]

Answer:

155.53

Step-by-step explanation:

I know where this question is from hahaha

6 0

3 years ago

Guys I need help with this one! USE BAR MODEL FOR THIS ONE

sveta [45]

16.5 because it would 165 divided by 10, so if you were to round it’s 17 because you can’t really get half a person.

7 0

3 years ago

For what value of x is sq 896z^15/225z^6 = xz^4/15

Ratling [72]

Answer:

Value of x is, 8

Step-by-step explanation:

Given: $\sqrt{\frac{896z^{15}}{225z^6}} =\frac{xz^4}{15} \sqrt{14z}$ ,.....[1]

To find the value of x:

Using exponent rules:

$(a^n)^m = a^{nm}$

$a^n \cdot a^m = a^{n+m}$

Taking square both sides in [1] we have;

$\frac{896z^{15}}{225z^6} = (\frac{xz^4}{15})^2 \cdot (14z)$

Simplify:

$\frac{896z^{15}}{225z^6} =\frac{x^2z^8}{225} \cdot (14z)$

$\frac{896z^{15}}{225z^6} =\frac{14x^2z^9}{225}$

Multiply both sides by $\frac{225}{14z^9}$ we get;

$x^2 = \frac{896 z^{15}}{225z^6} \times \frac{225}{14 z^9} = \frac{896 z^{15}}{14 z^{9+6}}$

Simplify:

$x^2 = \frac{896 z^{15}}{14 z^{15}} = 64$

$x = \sqrt{64}$

Simplify:

x = 8

Therefore, the value of x is, 8

5 0

3 years ago