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<h3>Answer:</h3>
- C. (9x -1)(x +4) = 9x² +35x -4
- B. 480
- A. P(t) = 4(1.019)^t
Step-by-step explanation:
1. See the attachment for the filled-in diagram. Adding the contents of the figure gives the sum at the bottom, matching selection C.
2. If we let "d" represent the length of the second volyage, then the total length of the two voyages is ...
... (d+43) + d = 1003
... 2d = 960 . . . . . . . subtract 43
... d = 480 . . . . . . . . divide by 2
The second voyage lasted 480 days.
3. 1.9% - 1.9/100 = 0.019. Adding this fraction to the original means the original is multiplied by 1 +0.019 = 1.019. Doing this multiplication each year for t years means the multiplier is (1.019)^t.
Since the starting value (in 1975) is 4 (billion), the population t years after that is ...
... P(t) = 4(1.019)^t
Answer:
<u>Fred.</u>
Started hang gliding at a height of 700 ft and descends 15 feet every seconds
<u>Gene</u>
Started hang gliding at a height of 575 ft and descends 10 feet every seconds
Step-by-step explanation:
The function that models Fred's hang gliding is
The initial value is 700 feet. This Fred was 700 feet above see level before he starts descending.
The rate of descent is -15 ft/s. This means Fred descends 15 feet in one second.
From the table the initial height is 575 ft. This means Gene was 575 feet above sea-level at the beginning of the hang gliding.
The rate of descent is ft/s.
This means that in every seconds, Gene descends 10 feet.