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TiliK225 [7]
3 years ago
15

The equation of line AB is y = 2x + 4. What is the equation of a line parallel to line AB in slope-intercept form that contains

the point (3,-2)?
Oy = 2x - 4
Oy=-*
Oy = 2x - 8
Mathematics
2 answers:
hodyreva [135]3 years ago
7 0

Answer:

Step-by-step explanation:

eq. of line parallel to AB is y=2x+a

if it passes through (3,-2) then

-2=2×3+a

a=-2-6=-8

y=2x-8

Nadusha1986 [10]3 years ago
4 0

Answer:

y = 2x - 8

Step-by-step explanation:

The equation of a straight line can be represented in the slope intercept form as

y = mx + c

Where

m = slope = (change in the value of y in the y axis) / (change in the value of x in the x axis)

The equation of the given line, AB is

y = 2x + 4

Comparing with the slope intercept form, slope = 2

If two lines are parallel, it means that they have the same slope. Therefore, the slope of the line passing through (3, -2) is 2

To determine the intercept, we would substitute m = 2, x = 3 and y = -2 into y = mx + c. It becomes

- 2 = 2×3 + c = 6 + c

c = - 2 - 6 = - 8

The equation becomes

y = 2x - 8

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