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worty [1.4K]
3 years ago
10

20 people applied for a job. Everyone either has a school certificate or diploma or even both. If 14 have school certificates an

d 11 diplomas how many have a school certificate only
Mathematics
1 answer:
STatiana [176]3 years ago
3 0

Given:

Either has a school certificate or diploma or even both = 20 people

Having school certificates = 14

Having diplomas = 11

To find:

The number of people who have a school certificate only.

Solution:

Let A be the set of people who have school certificates and B be the set of people who have diplomas.

According to the given information, we have

n(A)=14

n(B)=11

n(A\cup B)=20

We know that,

n(A\cup B)=n(A)+n(B)-n(A\cap B)

20=14+11-n(A\cap B)

20=25-n(A\cap B)

Subtract both sides by 25.

20-25=-n(A\cap B)

-5=-n(A\cap B)

5=n(A\cap B)

We need to find the number of people who have a school certificate only, i.e. n(A\cap B').

n(A\cap B')=n(A)-n(A\cap B)

n(A\cap B')=14-5

n(A\cap B')=9

Therefore, 9 people have a school certificate only.

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That is the first part of our solution. What we are actually looking for is an ordered pair. We know ordered pairs are written in the form (x, y). First, we need to find the 'x'. The 'x' has been given to us from the beginning, it is 4. Next is the 'y'. This is what we needed to find using substitution. We ultimately concluded that the 'y' is equivalent to 28. Therefore our ordered pair is (4, 28), the letter choice C.

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