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Scorpion4ik [409]
2 years ago
5

What are the zeros of the functions f(x)=x(x-2)/(x+3)(x-5)??

Mathematics
1 answer:
PSYCHO15rus [73]2 years ago
8 0

~~~~~~~\dfrac{x(x-2)}{(x+3)(x-5)}=0\\\\\\\implies x(x-2) = 0\\\\\\\implies x = 0,~ x  =2\\\\\text{The zeroes are}~ 0~ \text{and}~ 2.

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Paul paid $ 25.50 for 3 cups of hot chocolate and cups of tea. The cost of each cup of tea was 2/3 the cost of each cup of hoy c
Allushta [10]

Let the cost of one cup of hot chocolate  be = x

Let the cost of one cup of hot tea be = y

Paul paid $ 25.50 for 3 cups of hot chocolate and 4 cups of tea.

Equation becomes = 3x+4y=25.50   ...(1)

As given, the cost of each cup of tea was 2/3 the cost of each cup of hot chocolate.

y=\frac{2x}{3}   .... (2)

Putting the value of y from (2) in (1)

3x+4(\frac{2x}{3})=25.50

=3x+\frac{8x}{3}=25.50

=\frac{9x+8x}{3}=25.50

=17x=76.5

x=4.5

y=\frac{2x}{3}

=\frac{2*4.5}{3}

y =3

Hence each cup of hot chocolate is $4.50

Each cup of tea is $3.

7 0
3 years ago
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ivann1987 [24]

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In total there are 12 ounces. If she drinks 3/5 of 12 you multiply 3/5 by 12.

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Hope this helped!

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