Vertex form for a parabola with vertex (p,q) is
![y = a(x-p)^2 + q](https://tex.z-dn.net/?f=y%20%3D%20a%28x-p%29%5E2%20%2B%20q)
We have (p,q)=(-4,5) and another point (-3,2) so we can solve for <em>a:</em>
![2 = a(-3 - -4)^2 + 5](https://tex.z-dn.net/?f=2%20%3D%20a%28-3%20-%20-4%29%5E2%20%2B%205)
![2 = a + 5](https://tex.z-dn.net/?f=2%20%3D%20a%20%2B%205)
![a = -3](https://tex.z-dn.net/?f=a%20%3D%20-3)
Putting it together,
Answer: ![y = -3(x + 4)^2 + 5](https://tex.z-dn.net/?f=y%20%3D%20-3%28x%20%2B%204%29%5E2%20%2B%205)
We could multiply that out if we like but I won't bother.
B. Accuracy is if it's right or not. Precision is how many decimal places it goes out to. So it is precise but not accurate.
Answer:
14 ![\frac{1}{2}](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B2%7D)
Step-by-step explanation:
Answer:
B & C
Step-by-step explanation:
√16 / √100
= 4 / 10
= 2 / 5