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2 years ago

A 36-foot-tall tree casts a 9-foot shadow. How tall is a nearby tree that casts a 14-foot shadow at the same time?

Mathematics

1 answer:

kiruha [24]2 years ago

7 0

Answer:

Proportion states that the two fractions or ratios are equal.

Given the statement: A 36-foot-tall tree casts a 9-foot shadow.

To find the height of the nearby tree that cast a 14 foot shadow at the same time.

Let x be the height of the nearby tree.

By definition of proportion;

$\frac{\text{Height of thetall tree}}{\text{Shadow of the tall tree}} =\frac{\text{Height of the nearby tree}}{\text{Shadow of the nearby tree}}$

Substitute the given values we get;

$\frac{36}{9}=\frac{x}{14}$

Simplify:

$4 = \frac{x}{14}$

Multiply both sides by 14 we get;

$x= 4 \times 14 = 56$ foot.

therefore, the height of the nearby tree is, 56 foot.

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Drag each equation to show if it could be a correct first step to solving the equation 3(6+x)=24.

Aneli [31]

Answer:

Here you go

Step-by-step explanation:

Hope this helps :)

8 0

2 years ago

Cylinders A and B are similar. The volume of cylinder A is 20mm3. Calculate the volume of cylinder B.

MrRa [10]

The question is incomplete. The complete question is :

Cylinders A and B are similar. The length of the cylinder A is 4 mm and the length of cylinder B is 6 mm. The volume of cylinder A is 20mm3. Calculate the volume of cylinder B.

Answer:

67.5 $mm^3$

Step-by-step explanation:

Given that :

Cylinder A and cylinder B are similar.

Let volume of cylinder A = 20 $mm^3$

We know the volume of a cylinder is given by V = $\pi r^2 h$

where, r is the radius of the cylinder

h is the height of the cylinder

We have to find the scale factor.

The length scale factor is = $\frac{6}{4}$

$=\frac{3}{2}$

Area scale factor $=\left(\frac{3}{2}\right)^2$

$=\frac{9}{4}$

∴ Volume scale factor $=\left(\frac{3}{2}\right)^3$

$=\frac{27}{8}$

Therefore, the volume of cylinder B is $=20 \times \frac{27}{8}$

= 67.5 $mm^3$

5 0

2 years ago

A father’s age now is three times the age that his son was 4 years ago. In

Mice21 [21]

Let ‘s’ be the son’s age 12 years ago.
Let ‘f’ be the father’s current age.

4 years ago, the son was:

s-4

So, his father is currently:

3(s-4)

=

3s-12

Therefore:

f = 3s-12

In twelve years, the son will be:

s+12

And the father will be:

f+12

This can also be written as:

3s-12+12 as the fathers younger age would be f = 3s+12

=

3s

So, we know that s+12 is half the fathers current age, meaning the father is currently 2(s+12) which is equivalent to 2s+24. Also, we know that the father is currently 3 times the sons age 12 years ago, so 3s (proven by the calculations we made above). Therefore, 2s+24=3s which means 24=s. We can then substitute this, and we will receive 24+12 = 36

Son’s current age: 36

We then substitute the son’s age 12 years ago into 2s+24 to give us the father’s age.

2(24)+24 = 72

Father’s current age: 72

7 0

1 year ago

Ans the question...... very urgent

MArishka [77]

Answer:

The solution should be log7^3(49)-1/3log7(49)=1/3*2

B-2/3

8 0

2 years ago

Is 0.26 is closer to 0, 1/2 or, 1

professor190 [17]

Here, we know 1/2 = 0.50
So, the difference between 0.50 & 0.26 is 0.24
And difference between 0 and 0.26 is 0.26
1 is very apart from 0.26 as compared to other two

So, It is closer to 1/2

Hope this helps!

8 0

3 years ago

Read 2 more answers