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Luden [163]
3 years ago
14

100 points!!!!!! anyone who says "I don't know" or "Ii don't care" WILL be dealt with by a moderator I need someone to give me a

math problem for growth or decay where you give me the inital value function and the growth/decay function and I have to graph both and say how the function changed.
Mathematics
2 answers:
kondor19780726 [428]3 years ago
7 0

Hello!


We don't have anything to work with, how can we solve it if there is not anything to solve with?

Nadya [2.5K]3 years ago
5 0
Decay word problem:
Uranium-238 decays by 25% every 30 minutes, if you have 200g of Uranium-238, how much Uranium do you have after 4 hours?

Comment if you want the solution
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3 years ago
Which of the following is ..... below
prisoha [69]
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5 0
3 years ago
Make use of structure. For rectangle ABCD, two vertices are A(-2, 3) and B(4, 6). Find the slopes of BC, CD, and DA. Explain you
MrRissso [65]

We are given a rectangle ABCD

A(-2, 3)

B(4, 6)

We are asked to find the slopes of sides BC, CD, and DA.

Let me first draw a rectangle to better understand the problem

Recall that the slope is given by

m=\frac{y_2−y_1}{ x_2−x_1}\text{where}(x_1,y_1)=(-2,3)\text{and}(x_2,y_2)=(4,6)

So the slope of side AB is

m_{AB}=\frac{6-3}{4-(-2)}=\frac{3}{4+2}=\frac{3}{6}=\frac{1}{2}=0.5

The sides BC and DA are perpenducluar to the side AB.

So their slopes will be

m_{BC}=m_{DA}=\frac{1}{-m_{AB}}

Substituting the value of slope of AB

m_{BC}=m_{DA}=\frac{1}{-0.5}=-2

The side CD is parallel to the side AB.

Parallel sides have equal slopes so

m_{CD}=m_{AB}=\frac{1}{2}

Therefore, the slopes of the rectangle ABCD are

\begin{gathered} m_{AB}=m_{CD}=\frac{1}{2} \\ m_{BC}=m_{DA}=-2 \end{gathered}

3 0
1 year ago
(3√5)2 i got 45 bit my calculator says 15. ?
UkoKoshka [18]
So, (3√5)^2

So, 3√5(3√5)

3*3 is 9
and √5*√5 is 5

9*5 is 45.
3 0
3 years ago
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