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Ilia_Sergeevich [38]
2 years ago
8

What is (x^4)/(x^0)?

Mathematics
1 answer:
e-lub [12.9K]2 years ago
4 0

Answer:

x^2+4x

Step-by-step explanation:

Use the Foil formula

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Write the scientific notation for 2,460,000
Diano4ka-milaya [45]
It would be equalto 2.4 * 10^6
4 0
3 years ago
Find the value of X(2x + 4) (2x-9)
kotykmax [81]

2x +4)° 2x-9)°= 4x  2 +8x−9=3

 Pull out like factors :

  2x + 4  =   2 • (x + 2) (4 • (x + 2) • x) -  9

4x • (x + 2) -  9

Factoring  4x2+8x-9  

The first term is,  4x2  its coefficient is  4 .

The middle term is,  +8x  its coefficient is  8 .

The last term, "the constant", is  -9  

Step-1 : Multiply the coefficient of the first term by the constant   4 • -9 = -36  

Step-2 : Find two factors of  -36  whose sum equals the coefficient of the middle term, which is   8 .

     -36    +    1    =    -35  

     -18    +    2    =    -16  

     -12    +    3    =    -9  

     -9    +    4    =    -5  

     -6    +    6    =    0  

     -4    +    9    =    5  

     -3    +    12    =    9  

     -2    +    18    =    16  

     -1    +    36    =    35

x=3

6 0
2 years ago
Read 2 more answers
What value of b with cause the system to have an infinite number of solutions?
Rom4ik [11]

Step-by-step explanation:

-3x+3x-(b÷2)=-3

0-(b÷2)=-3

-(b÷2)=-3

b=-2×-3=+6

=> b=6

5 0
3 years ago
Which equation represents a parabola that opens upward, has a minimum value of 3, and has an axis of symmetry at x= 3?
Ilya [14]

Answer:

y=(x-3)^2+3

Step-by-step explanation:

<u><em>The correct question is</em></u>

Which equation represents a parabola that opens upward, has a minimum value of y=3, and has an axis of symmetry at x= 3?

<em>Verify each case</em>

case 1) we have

y=(x+3)^2-6

This a vertical parabola open upward (the leading coefficient is positive)---> is ok

The vertex represent a minimum ---> is ok

The vertex is the point (-3,-6)

The minimum value of y=-6 ----> is not ok

The axis of symmetry is x=-3 ----> is not ok

case 2) we have

y=(x+3)^2+3

This a vertical parabola open upward (the leading coefficient is positive)---> is ok

The vertex represent a minimum ---> is ok

The vertex is the point (-3,3)

The minimum value of y=3 ----> is ok

The axis of symmetry is x=-3 ----> is not ok

case 3) we have

y=(x-3)^2-6

This a vertical parabola open upward (the leading coefficient is positive)---> is ok

The vertex represent a minimum ---> is ok

The vertex is the point (3,-6)

The minimum value of y=-6 ----> is not ok

The axis of symmetry is x=3 ----> is ok

case 4) we have

y=(x-3)^2+3

This a vertical parabola open upward (the leading coefficient is positive)---> is ok

The vertex represent a minimum ---> is ok

The vertex is the point (3,3)

The minimum value of y=3 ----> is ok

The axis of symmetry is x=3 ----> is ok

6 0
3 years ago
Which table of values will generate this graph? On a coordinate plane, points are at (negative 2, 0), (0, 1), (0, negative 4), a
zhuklara [117]

Answer:

Option D.

Step-by-step explanation:

The given points are (-2,0), (0,1), (0,-4) and (3,0).

In each ordered pair first element is x-coordinate and second is y-coordinate.

For 4 points, the table must have 2 columns and 4 rows.

So, the required table of values is

x         y

-2        0

0       -4

0        1

3        0

Therefore, the correct option is D.

5 0
3 years ago
Read 2 more answers
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