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IRISSAK [1]
3 years ago
10

Pleaseee Help. Don't answer if you aren't going to take it serious.

Mathematics
1 answer:
Nadya [2.5K]3 years ago
6 0
<span>Stem-and-leaf plots are used for showing the frequency of which certain classes of values occur. use a stem-and-leaf plot and let the numbers themselves to show pretty much the same information. In short, they are meant to show frequencies of which numbers or values occur. Not for colors or objects.

Yes, a frequency table is a perfect way to solve the problem! These are meant to help you find the number of something that occurs, and is a simple and clean way to show your word.</span>
You might be interested in
Which expression represents the correct form for the quotient and remainder, written as partial fractions, of
Oduvanchick [21]

Answer:

  • C)~A+ \frac{B}{x-3} +\frac{c}{(x-3)^2}

Step-by-step explanation:

→ \frac{(7x^2-40x+52)}{(x^2-6x+9)}

→ \frac{7x^2-40x+52}{x^2-2.3x+(3)^2}

→  \frac{7x^2-40x+52}{(x-3)^2}

<u>So, your answer is C</u>

<u></u>----------<u></u>

<u>hope it helps...</u>

<u>have a great day!!</u>

8 0
3 years ago
State the domain and the range of each relation. Then determine whether the relation is a function.
IrinaVladis [17]

Answer:

Domain:{-6,3,4}

Range:{-2,5,6,23}

The relation is not a function.

Step-by-step explanation:

By definition, a relation is a function if each input value has only one output value.

Given the relation:

(4,23)

(3,-2)

(-6,5)

(4,6)

The domain is the set of the x-coordinates of each ordered pair (You do not need to write 4 twice):

Domain:{-6,3,4}

The range is the set of the y-coordinates of each ordered pair :

 Range:{-2,5,6,23}

Since the input value 4 has two different output values (23 and 6), the relation is not a function.

8 0
3 years ago
Read 2 more answers
Round 5049 correct to 1 significant figure​
Step2247 [10]

5000

  • Addition (+) and subtraction (-) round by the least number of decimals.
  • Multiplication (* or ×) and division (/ or ÷) round by the least number of significant figures.
  • Logarithm (log, ln) uses the input's number of significant figures as the result's number of decimals.
  • Antilogarithm (n^x.y) uses the power's number of decimals (mantissa) as the result's number of significant figures.
  • Exponentiation (n^x) only rounds by the significant figures in the base.
  • To count trailing zeros, add a decimal point at the end (e.g. 1000.) or use scientific notation (e.g. 1.000 × 10^3 or 1.000e3).
  • Zeros have all their digits counted as significant (e.g. 0 = 1, 0.00 = 3).
  • Rounds when required, after parentheses, and on the final step.

<em>-</em><em> </em><em>BRAINLIEST </em><em>answerer</em><em> ❤️</em>

7 0
2 years ago
Read 2 more answers
Check the true statements below:
valentinak56 [21]

Answer:

a) False

b) False

c) True

d) False

e) False

Step-by-step explanation:

a. A single vector by itself is linearly dependent. False

If v = 0 then the only scalar c such that cv = 0 is c = 0. Hence, 1vl is linearly independent. A set consisting of a single vector v is linearly dependent if and only if v = 0. Therefore, only a single zero vector is linearly dependent, while any set consisting of a single nonzero vector is linearly independent.

b. If H= Span{b1,....bp}, then {b1,...bp} is a basis for H. False

A sets forms a basis for vector space, only if it is linearly independent and spans the space. The fact that it is a spanning set alone is not sufficient enough to form a basis.

c. The columns of an invertible n × n matrix form a basis for Rⁿ. True

If a matrix is invertible, then its columns are linearly independent and every row has a pivot element. The columns, can therefore, form a basis for Rⁿ.

d.  In some cases, the linear dependence relations among the columns of a matrix can be affected by certain elementary row operations on the matrix. False

Row operations can not affect linear dependence among the columns of a matrix.

e. A basis is a spanning set that is as large as possible. False

A basis is not a large spanning set. A basis is the smallest spanning set.

3 0
3 years ago
Due to ever-changing technology, a new XYZ Smartphone decreases in value 20% each year. (a) How much will this $1000 phone be wo
neonofarm [45]

Answer:

1.) $640 2.) 7 years.

Step-by-step explanation:

1000 x .2 = 200      1 yr

1000 - 200 = 800

800 x .2 = 160         2 yrs

800 - 160 = 640

640 x .2 = 128         3 yrs

640 - 128 = 512

ANYWAYS THIS WOULD TAKE TO LONG! SO HERE IS THE ANSWER TO B.

5 0
3 years ago
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