Drag each tile to the correct box. Graph the functions as transformations of f(x)=x^2. Arrange the parabolas with respect to the
1 answer:
If a constant is added to a variable then the graph gets shifted toward left and vice-versa. Then the graphs are shown below.
<h3>What is the parabola?</h3>It's the locus of a moving point that keeps the same distance between a stationary point and a specified line. The focus is a non-movable point, while the directrix is a non-movable line.
The parabola is given below.
f(x) = x²
Then the parabolas with respect to the position of their vertices from left to right will be
1: y = f(x) = x²
2: y = f(x - 4) = (x - 4)²
3: y = f(x + 3) = (x + 3)²
4: y = f(x - 7) = (x - 7)²
5: y = f(x + 2) = (x + 2)²
6: y = f(x - 1/2) = (x - 1/2)²
The graph of the parabola is given below.
More about the parabola link is given below.
#SPJ1
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Answer:
The interval (meassured in Inches) that represent the middle 80% of the heights is [64.88, 75.12]
Step-by-step explanation:
I beleive those options corresponds to another question, i will ignore them. We want to know an interval in which the probability that a height falls there is 0.8.
In such interval, the probability that a value is higher than the right end of the interval is (1-0.8)/2 = 0.1
If X is the distribuition of heights, then we want z such that P(X > z) = 0.1. We will take W, the standarization of X, wth distribution N(0,1)
The values of the cumulative distribution function of W, denoted by , can be found in the attached file. Lets call
. We have
Thus
by looking at the table, we find that y = 1.28, therefore
The other end of the interval is the symmetrical of 75.12 respect to 70, hence it is 70- (75.12-70) = 64.88.
The interval (meassured in Inches) that represent the middle 80% of the heights is [64.88, 75.12] .