All categories

2 years ago

Use the graph below to answer questions 1 and 2.

Mathematics

1 answer:

saul85 [17]2 years ago

4 0

Answer:

x-intercept is x = -4; y-intercept is y = -2

Step-by-step explanation:

The zero or x-intercept is when the line touches the x-axis or horizontal line axis or is when y = 0.

x = -4

The y-intercept is when the line touches the y-axis or vertical line axis or is when x = 0.

y = -2

You might be interested in

Find a polynomial of degree 3 with a real coefficient that satisfies the given condition. Zeros: -2, 1, 0; f(2)=32

xz_007 [3.2K]

Its factors would be
(x+2)*(x-1)*(x+0)

x^2 +x -2

x^3 + 0 + x^2 + 0 -2x +0

Equation: x^3 + x^2 -2x
f(2) = 8 + 4 -4

2x^3 + 2x^2 -4x +0
f(2) = 16 + 8 -8

3x^3 + 3x^2 -6x +0
f(2) = 24 +12 -12

4x^3 + 4x^2 -8x +0
f(2) = 32 +16 -16

So, the equation is:
4x^3 + 4x^2 -8x = 0

8 0

2 years ago

What is the y-intercept of the graph of the equation y = 2(x - 3)² + 7? -3 6 7 25

babunello [35]

The y-intercept would be 25, if you want to find the y-intercept, plug in zero for x!

6 0

2 years ago

HELP! WILL GIVE BRANLIEST!

avanturin [10]

Answer: 5 Hope this helped-

7 0

2 years ago

I need the answer written

padilas [110]

Answer:

x = 180 - (31 + 40)

Step-by-step explanation:

x = 180 - (31 + 40)

5 0

2 years ago

Read 2 more answers

Semicircles and quarter circles are types of arc lengths. Recall that an arc is simply part of a circle. We learned about the de

attashe74 [19]

The question is incomplete. Here is the complete question.

Semicircles and quarter circles are types of arc lengths. Recall that an arc is simply part of a circle. we learned about the degree measure of an ac, but they also have physical lengths.

a) Determine the arc length to the nearest tenth of an inch.

b) Explain why the following proportion would solve for the length of AC below: $\frac{x}{12\pi } = \frac{130}{360}$

c) Solve the proportion in (b) to find the length of AC to the nearest tenth of an inch.

Note: The image in the attachment shows the arc to solve this question.

Answer: a) 9.4 in

c) x = 13.6 in

Step-by-step explanation:

a) $\frac{arclength}{2\pi.r } = \frac{mAB}{360}$ , where:

r is the radius of the circumference

mAB is the angle of the arc

arc length = $\frac{mAB.2.\pi.r }{360}$

arc length = $\frac{90.2.3.14.6}{360}$

arc length = 9.4

The arc lenght for the image is 9.4 inches.

b) An arc length is a fraction of the circumference of a circle. To determine the arc length, the ratio of the length of an arc to the circumference is equal to the ratio of the measure of the arc to 360°. So, suppose the arc length is x, for the arc in (b):

$\frac{x}{2.6.\pi } = \frac{130}{360}$

$\frac{x}{12\pi } = \frac{130}{360}$

c) Resolving (b):

x = $\frac{130.12.3.14}{360}$

x = 13.6

The arc length for the image is 13.6 inches.

6 0

2 years ago