Answer:
I'm sorry I just started 5th grade a week ago
Answer:
20
Step-by-step explanation:
A data is given and the mean of data is 19.6 .The data is ,
12 , 16 , 22 , x , 28 .
We know that the mean is sum of observations divided by Total number of observations . So that ,
⇒ 12 + 16 + 22 + x + 28/ 5 = 19.6
⇒ 78+x/5 = 19.6
⇒ 19.6 × 5 = 78 + x
⇒ 78 + x = 98
⇒ x = 98 - 78
⇒ x = 20
<h3>
<u>Hence </u><u>the</u><u> value</u><u> of</u><u> </u><u>x</u><u> </u><u>is</u><u> </u><u>2</u><u>0</u><u> </u><u>.</u></h3>
The points A and B and the center O of the circle form a right angle and AO = radius.
So by Pythagoras
16^2 = 15^2 + AO^2
AO = sqrt (16^2 - 15^2)
AO ( radius) = sqrt31 = 5,57 feet answer (to nearest hundredth)
Answer:
umm hol up lemme think about it
Step-by-step explanation:
Answer:
Part 1) The trapezoid has an area of 
Part 2) The kite has an area of
Part 3) The area of the trapezoid is less than the area of the kite
Step-by-step explanation:
Part 1
Find the area of trapezoid
we know that
The area of trapezoid is equal to the area of two congruent triangles plus the area of a rectangle
so
![A=2[\frac{1}{2} (2)(5)]+(2)(5)](https://tex.z-dn.net/?f=A%3D2%5B%5Cfrac%7B1%7D%7B2%7D%20%282%29%285%29%5D%2B%282%29%285%29)
Part 2
Find the area of the kite
we know that
The area of the kite is equal to the area of two congruent triangles
so
![A=2[\frac{1}{2} (7)(3)]=21\ m^2](https://tex.z-dn.net/?f=A%3D2%5B%5Cfrac%7B1%7D%7B2%7D%20%287%29%283%29%5D%3D21%5C%20m%5E2)
Part 3
Compare the areas
The trapezoid has an area of 
The kite has an area of
so

therefore
The area of the trapezoid is less than the area of the kite