Answer: let me check
Step-by-step explanation:
If there is 20 pencils there will be 5 erasers 20:5
The answer to the question asked is 5.
The least common multiple of 4 and 6 is 12. In the range 140 to 200, there are
... floor(200/12) - ceiling(140/12) + 1 = 16 - 12 + 1 = 5
integers divisible by 12.
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The list of answer choices suggests that the question is intended to be, "how many integers are divisible by 4 or 6?"
The number divisible by 4 is
... floor(200/4) - ceiling(140/4) + 1 = 50 - 35 + 1 = 16
The number divisible by 6 is
... floor(200/6) - ceiling(140/6) + 1 = 33 - 24 + 1 = 10
We know from the above that there are 5 values that are divisible by both 4 and 6, so will be counted twice if we simply add the above numbers. Hence the number of values divisible by 4 or 6 is
... 16 + 10 - 5 = 21 . . . . . corresponds to selection C)
The solution (-4,2) satisfies for the system of linear equations 3x + 13y = 14; 6x + 11y = -2
<u>Step-by-step explanation:</u>
Step 1:
Given detail is the solution of the equations (-4, 2) ie, x= - 4 and y = 2
This implies that this solution should satisfy the given linear equations.
Step 2:
Substitute values of x and y in the equations and verify whether the right hand side equals the left hand side.
System 1 Eq(1) ⇒ LHS = 3(-4) + 13 (2) = -12 + 26 = 14 = RHS
System 1 Eq(2) ⇒ LHS = 6(-4) + 11(2) = -24 + 22 = -2 = RHS
Therefore, the first system of linear equations satisfy the condition.
Answer:
Step-by-step explanation:
Add 6 to both sides:
Subtract 9m from both sides:
Divide both sides by -3:
