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3 years ago

3.) AI 65 kom hr. Alfred can reach home in 50 minutes. At what speed should he drive his car

Mathematics

1 answer:

Yanka [14]3 years ago

8 0

Answer:

He should drive his car at a speed of 81.25 kilometers per hour.

Step-by-step explanation:

With a velocity of 65 kilometers per hour, he reaches home in 50 minutes. What speed he needs to reach home 10 minutes earlier, that is, in 50 - 10 = 40 minutes?

To solve this, we use the relation between inverse proportion variables(as the velocity increases, time needed decreases), that is, a rule of three with line multiplication, instead of cross. So

65 kilometers per hour - 50 minutes

x kilometers per hour - 40 minutes

$40x = 65*50$

$x = \frac{65*50}{40}$

$x = 81.25$

He should drive his car at a speed of 81.25 kilometers per hour.

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Answer:

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Step-by-step explanation:

We need to choose Pythagoras theorem formula

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option-B

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3 years ago

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3 years ago

1. The area of a circle is 60 square units. What is the area of ...

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Answer:

Step-by-step explanation:

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3 years ago

Consider the initial value problem:

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Answer:

$\left \{ {{u'=v} \atop {v'=5v-6u-5\sin(2t)}} \right. \\u(0)=-5;u'(0)=2$

Step-by-step explanation:

The given initial value problem is;

$y''-5y'+6y=-5\sin(2t)---(1)\\y(0)=-5,y'(0)=2$

Let

$u(t)=y(t)----(2)\\v(t)=y'(t)----(3)$

Differentiating both sides of equation (1) with respect to $t$ , we obtain:

$u'(t)=y'(t)---(4)\\ \\\implies u'(t)=v(t)---(5)$

Differentiating both sides of equation (2) with respect to $t$ gives:

$v'(t)=y''(t)----(6)$

From equation (1),

$y''=5y'-6y-5\sin(2t)\\y''=5v(t)-6u(t)-5\sin(2t)\\\implies v'(t)=5v(t)-6u(t)-5\sin(2t)----(7)$

Putting t=0 into equation (2) yields

$u(0)=y(0)\\\implies u(0)=-5$

Also putting t=0 into equation (3)

$u'(0)=y'(0)\\u'(0)=2$

The system of first order equations is:

$\left \{ {{u'=v} \atop {v'=5v-6u-5\sin(2t)}} \right. \\u(0)=-5;u'(0)=2$

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4 years ago

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