A rectangle with sides 15 and w has perimeter

We want this quantity to be at most 50, so it must be less than or equal to 50:

For the record, this implies that

So, the width can be at most 10.
Answer:
800,049
Step-by-step explanation:
i hope this helps
THE PARABOLA OPENS DOWN (WHICH IS MAXIMUM ) AND X=1/2
Answer:
Step-by-step explanation:
Step-by-step explanation:
Familiarize yourself with perfect squares in the neighborhood of 140:
10^2 = 100
11^2 = 121
12^2 = 144
Note that 140 is much closer to the perfect square than it is to the perfect square 121. The value of √140 must lie closer to 12 than to 11.
Place a point on the number line about 3/4 of the way from 11 to 12.
Step-by-step explanation:
