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Mariana [72]
3 years ago
11

Use a calculator to find 5 as a percentage of 135 correct to 1 decimal place.

Mathematics
1 answer:
stich3 [128]3 years ago
7 0

Step-by-step explanation:

\frac{5}{135}  \times 100\% = 3.703\% \\  \\  = 3.7\%

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Verizon is implementing a new program based on the number of connected devices in each household. Currently, customers are charg
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d

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3 years ago
The arithmetic sequence a; is defined by the formula:
Morgarella [4.7K]

Answer:

The sum of the first 650 terms of the given arithmetic sequence is 2,322,775

Step-by-step explanation:

The first term here is 4

while the nth term would be ai = a(i-1) + 11

Kindly note that i and 1 are subscript of a

Mathematically, the sum of n terms of an arithmetic sequence can be calculated using the formula

Sn = n/2[2a + (n-1)d)

Here, our n is 650, a is 4, d is the difference between two successive terms which is 11.

Plugging these values, we have

Sn = (650/2) (2(4) + (650-1)11)

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6 0
3 years ago
WHAT IS THE SUM OF 76/81 X 80/76
Advocard [28]

Answer:

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Step-by-step explanation:

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6 0
2 years ago
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Emily took 300 US dollars to the bank to exchange it for Canadian dollars. The exchange rate on that day was 1.25 Canadian dolla
Paha777 [63]

Emily wanted to exchange her 300 US Dollars for Canadian Dollars.

The exchange rate for it was 1.25 Canadian Dollars for 1 US Dollar.

This means that 1 US Dollar = 1.25 Canadian Dollars.

So if we were to follow this pattern,

2 US Dollars = 2 × 1.25 = 2.5 Canadian Dollars

3 US Dollars = 3 × 1.25 = 3.75 Canadian Dollars

4 US Dollars = 4 × 1.25 = 5 Canadian Dollars

So for 300 US Dollars, we'll need to multiply 300 by 1.25.

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4 0
2 years ago
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nataly862011 [7]

Answer:

Mean

Step-by-step explanation:

Given

Data: 4, 4, 2, 4, 4, 1, 3, 4, 2, 4

Required

Best measure of center

The mean is considered the best measure of center when there are no outliers in the given data.

Outlier is when a particular data set is far away from other datasets.

For instance: 20 is an outlier in the following data sets: 4, 4, 2, 20, 4, 4, 1, 3, 4, 2, 4

Also, the given data are not open-ended.

An open-ended data is as follows: 1, 2, 3, 4, 5\ or\ more

Since we do not have any of the above conditions, then the mean is the best center to use.

7 0
2 years ago
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