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wolverine [178]
2 years ago
8

What equation matches the known dimensions of the prism below? Prism with a volume of thirty six cubic inches; ? in., 4 in., 3 i

n. 4 × 3 × ? = 36 36 × ? × 4 = 3 4 × 3 × 36 = ? 36 × 3 × ? = 4
Mathematics
1 answer:
tatiyna2 years ago
7 0

Answer:

4 x 3 x ? = 36

Step-by-step explanation:

36 is quotient and we have 3 other numbers one we don't know so we simply do 4 x 3 x ? or the other way around.

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David cast a shadow 42" long at the same place and time in Emma cast a shadow 28" long. David is 66" tall. What is Emma's height
Nikolay [14]

ANSWER

Emma is 44" tall

EXPLANATION

We have that David cast a shadow 42 inches long and he is 66 inches tall.

At that same place and time, Emma cast a shadow of 28 inches.

Since they are at the same spot and time, we can conclude that the ratio of their height to shadow must be the same.

Let Emma's height be x.

The ratio of David's shadow to height is:

42 : 66 or 42 / 66

For Emma, it is:

28 : x or 28 / x

That means that:

\begin{gathered} \frac{42}{66}\text{ = }\frac{28}{x} \\ \text{Solve for x by cross-multiplying:} \\ 42\cdot\text{ x = 66 }\cdot\text{ 28} \\ x\text{ = }\frac{66\cdot\text{ 28}}{42} \\ x\text{ = 44 inches} \end{gathered}

So, Emma is 44" tall.

3 0
1 year ago
I'll mark brainly pls do this​
lidiya [134]

Step-by-step explanation:

Verbs are read, complete, checked, work, invite. Pronouns are their, your, and them. Nouns are Classroom, Zeroes, Friday, February, friends, assignment, students, trimester. Adjectives are simple, missing.

Hope this helps! If I missed some or got some wrong, please tell me! Goodbye!

8 0
3 years ago
Read 2 more answers
Estimate the integral ∫6,0 x^2dx by the midpoint estimate, n = 6
Anettt [7]
Splitting up the interval [0, 6] into 6 subintervals means we have

[0,1]\cup[1,2]\cup[2,3]\cup\cdots\cup[5,6]

and the respective midpoints are \dfrac12,\dfrac32,\dfrac52,\ldots,\dfrac{11}2. We can write these sequentially as {x_i}^*=\dfrac{2i+1}2 where 0\le i\le5.

So the integral is approximately

\displaystyle\int_0^6x^2\,\mathrm dx\approx\sum_{i=0}^5({x_i}^*)^2\Delta x_i=\frac{6-0}6\sum_{i=0}^5({x_i}^*)^2=\sum_{i=0}^5\left(\frac{2i+1}2\right)^2

Recall that

\displaystyle\sum_{i=1}^ni^2=\frac{n(n+1)(2n+1)}6
\displaystyle\sum_{i=1}^ni=\frac{n(n+1)}2
\displaystyle\sum_{i=1}^n1=n

so our sum becomes

\displaystyle\sum_{i=0}^5\left(\frac{2i+1}2\right)^2=\sum_{i=0}^5\left(i^2+i+\frac14\right)
=\displaystyle\frac{5(6)(11)}6+\frac{5(6)}2+\frac54=\frac{143}2

8 0
3 years ago
Help ill give brainlest pls
Setler [38]
I the answer To You Problem Is C
6 0
2 years ago
Find the exact value of tan 15 degrees
pentagon [3]
<span>tan(15) = 
sin(15) / cos(15) = 
sin(45 - 30) / cos(45 - 30) = 
[ sin(45)cos(30) - sin(30)cos(45) ] / [ cos(45)cos(30) + sin(45)sin(30)] 

Since sin(45) = cos(45) = √2/2, you can just factor that out from the top and bottom 
[ cos(30) - sin(30) ] / [ cos(30) + sin(30)] 
[ √3/2 - 1/2 ] / [ √3/2 + 1/2] 
(√3 - 1) / (√3 + 1) 
(√3 - 1)^2 / (√3+1)(√3 - 1) 
(√3 - 1)^2 / (3 - 1) 
(3 - 2√3 +1) / 2 
2 - √3 

There's also a formula for tan(a-b), but I couldn't remember it off hand.</span>
4 0
3 years ago
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