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beks73 [17]
3 years ago
10

Does anyone know the answer to this?

Mathematics
1 answer:
mr Goodwill [35]3 years ago
7 0

Answer:

I think she has about 3 segments for sprinting and 6 segments for jogging

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For this problem you need to put the x values in for x in the equation. For example, put -10 in for x and calculate y, which is g(x)
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What is |-8| ? -16
olga nikolaevna [1]

Answer:

8

Those little "sticks" are called absolute value.

For example, the absolute value of 2 is 2, and the absolute value of −2 is also 2. The absolute value of a number may be thought of as its distance from zero along real number line.

Thus, it doesn't matter if the number is positive or negative. As it only counts its <u>d</u><u>i</u><u>s</u><u>t</u><u>a</u><u>n</u><u>c</u><u>e</u><u> </u><u>f</u><u>r</u><u>o</u><u>m</u><u> </u><u>0</u><u>,</u><u> </u><u>o</u><u>n</u><u> </u><u>t</u><u>h</u><u>e</u><u> </u><u>n</u><u>u</u><u>m</u><u>b</u><u>e</u><u>r</u><u> </u><u>l</u><u>i</u><u>n</u><u>e</u><u>.</u>

I hope it helps.

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7 journals is the answer
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3 years ago
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Solve 2cos ²y -siny -1=0 for 0° ≤y≤360°
natima [27]

 

\displaystyle\bf\\2cos^2y -sin\,y -1=0~~~for~~0^o\leq y \leq360^o\\\\cos^2y=1-sin^2y\\\\2(1-sin^2y) -sin\,y -1=0\\\\2-2sin^2y-sin\,y-1=0\\\\-2sin^2y-sin\,y+2-1=0\\\\-2sin^2y-sin\,y+1=0~~~\Big|\times(-1)\\\\2sin^2y+sin\,y-1=0

.

\displaystyle\bf\\\boxed{\bf sin\,y=x}\\\\2x^2+x-1=0\\\\x_{12}=\frac{-b\pm\sqrt{b^2-4ac}}{2a}=\frac{-1\pm\sqrt{1-4\cdot2\cdot(-1)}}{2\cdot2}=\\\\=\frac{-1\pm\sqrt{1+8}}{4}=\frac{-1\pm\sqrt{9}}{4}=\frac{-1\pm3}{4}\\\\x_1=\frac{-1+3}{4}=\frac{2}{4}=\boxed{\bf\frac{1}{2}}\\\\x_2=\frac{-1-3}{4}=\frac{-4}{4}=\boxed{\bf-1}\\\\sin\,y=\frac{1}{2}\\\\\boxed{\bf y_1=\frac{\pi}{6}~~or~~(30^o)}\\\\\boxed{\bf y_2=\frac{5\pi}{6}~~or~~(150^o)}\\\\sin\,y=-1\\\\\boxed{\bf y_3=\frac{3\pi}{2}~~or~~(270^o)}

 

 

5 0
2 years ago
A researcher wishes to conduct a study of the color preferences of new car buyers. Suppose that 40% 40 % of this population pref
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Answer: 60% would like another color

Step-by-step explanation:

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