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2 years ago

2+2 is 4 minus 1 thats 3 quick mafs

Mathematics

2 answers:

PtichkaEL [24]2 years ago

7 0

Everyday man’s on the block…

Fittoniya [83]2 years ago

6 0

Answer: everyday mans on the block

Step-by-step explanation:

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Prove that: [1 + 1/tan²theta] [1 + 1/cot² thata] = 1/(sin²theta - sin⁴theta]

Stels [109]

Step-by-step explanation:

<h3><u>Given :-</u></h3>

[1+(1/Tan²θ)] + [ 1+(1/Cot²θ)]

<h3><u>Required To Prove :-</u></h3>

[1+(1/Tan²θ)]+[1+(1/Cot²θ)] = 1/(Sin²θ-Sin⁴θ)

<h3><u>Proof :-</u></h3>

On taking LHS

[1+(1/Tan²θ)] + [ 1+(1/Cot²θ)]

We know that

Tan θ = 1/ Cot θ

and

Cot θ = 1/Tan θ

=> (1+Cot²θ)(1+Tan²θ)

=> (Cosec² θ) (Sec²θ)

Since Cosec²θ - Cot²θ = 1 and

Sec²θ - Tan²θ = 1

=> (1/Sin² θ)(1/Cos² θ)

Since , Cosec θ = 1/Sinθ

and Sec θ = 1/Cosθ

=> 1/(Sin²θ Cos²θ)

We know that Sin²θ+Cos²θ = 1

=> 1/[(Sin²θ)(1-Sin²θ)]

=> 1/(Sin²θ-Sin²θ Sin²θ)

=> 1/(Sin²θ - Sin⁴θ)

=> RHS

=> LHS = RHS

<u>Hence, Proved.</u>

<h3><u>Answer:-</u></h3>

[1+(1/Tan²θ)]+[1+(1/Cot²θ)] = 1/(Sin²θ-Sin⁴θ)

<h3><u>Used formulae:-</u></h3>

→ Tan θ = 1/ Cot θ

→ Cot θ = 1/Tan θ

→ Cosec θ = 1/Sinθ

→ Sec θ = 1/Cosθ

<h3><u>Used Identities :-</u></h3>

→ Cosec²θ - Cot²θ = 1

→ Sec²θ - Tan²θ = 1

→ Sin²θ+Cos²θ = 1

Hope this helps!!

7 0

2 years ago

PLS HELP WILL MARK YOU BRAINLIEST! NO FAKE ANSWERS!

leonid [27]

⚘<em>Refer to the attachments for solution!!~</em>

8 0

2 years ago

A blueprint for a building includes a rectangular room that measures 3 inches long and 5.5 inches wide. The scale for the bluepr

Ganezh [65]

Answer:

30 ft. x 55ft

Step-by-step explanation:

3 x 5.5

1 inch = 10 ft

3 * 10 = 30

5.5 = 55

30' x 55'

4 0

2 years ago

Nancy is knitting a scarf. It takes her 0.2 of an hour to knit each inch of the scarf. She wants the length of the scarf to be 6

ehidna [41]

Answer:

2 hours

Step-by-step explanation:

60 *20

3 0

3 years ago

Read 2 more answers

The graph of a linear function intersects with the x axis at a point with an abscissa of 4 and with the y axis at a point with a

goldenfox [79]

We know that

points are
x intercept
A (4,0)

y intercept
B (0,11)

step 1
find the equation of a line
m=(y2-y1)/(x2-x1)--------> m=(11-0)/(0-4)------> m=-11/4

with m and the point B (0,11)
y-y1=m*(x-x1)y-11=(-11/4)*(x-0)---------> y=-(11/4)x+11

the answer is
the formula of the function is y=-(11/4)x+11

see the attached figure

7 0

3 years ago