Please help! This homework is by tomorrow

If you sketch the path of the boat, you will form a right triangle towards the port. The distance from the port to the present position is the hypotenuse since it is opposite from the right angle formed by the 12 miles north and 5 miles east movement. Since it is a right triangle, use the Pythagorean Theorem to solve the hypotenuse.

Solution:

h² = o² + a²
h² = 12² + 5²
h² = 144 + 25
h² = 169
√h² = √169
h= 13

The present distance of the boat from the port is 13 miles.

7 0

2 years ago

A rectangular swimming pool measures 40 ft by 60 ft and is surrounded by a path of uniform width around the four edges. The peri

Alex_Xolod [135]

Answer:

6ft

Step-by-step explanation:

Lets x = the width of the path the surrounding path will add 2x to the pool dimension,therefore over all dimesion: (2x+40) by (2x+60) the overall perimeter (2x + 40) + 2(2x+60) = 248 Simplify divide by 2, result (2x+40) +(2x+60) = 124

 Combine like terms 2x + 2x +40 +60 =124 

4x + 100 = 124 

4x=124 = 100

4x=24

x=24/4

x= 6ft is the width of the path

check this by finding the perimeter with these values; 2x = 12 ft 

2 ( 12 + 40 ) + 2( 12 +60 ) 

2( 52 + 2(72)

104 + 144 = 248; confirms our solution of x= 6 ft

5 0

3 years ago

You start driving north for 16 miles, turn right, and drive east for another 30 miles. At the end of driving, what is your strai

Maru [420]

The distance between starting and ending point is 34 miles.

Step-by-step explanation:

Given,

Car moves 16 miles to north then 30 mile to east.

It forms a right angle triangle.

The straight line distance from starting to ending point represents hypotenuse.

To find the distance between starting and ending point.

Formula

By Pythagoras theorem,

h² = b²+l² where h is the hypotenuse, b is base and l is the another side.

Taking, b=16 and l=30 we get,

h² = 16²+30²

or, h = $\sqrt{256+900}$

or, h = $\sqrt{1156}$ = 34

Hence,

The distance between starting and ending point is 34 miles.

5 0

3 years ago