Please help! This homework is by tomorrow
1 answer:
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Answer:
Mean = 0
Variance = 4/3
Standard Deviation √4/3
a= 0.9
Step-by-step explanation:
If X has a uniform distribution over [a,b] then its Mean is a+b/2 and variance is (b-a)²/12
Here a= -2 and b= 2
Now finding the mean = a+b/2=-2+2/2= 0
Variance = (b-a)²/12=( 2-(-2))²/12= 4²/12= 16/12= 4/3
Standard Deviation = √Variance= √4/3
b) = \int\limits^a_a {\frac{1}{a- (-a)} } \, dx
=1/2a[x]^a_-a= 2a/2a= 1 (applying the limits to the function)
P(−a<X<a) ==1/2 * 2a= a (applying the limits to the function)
P(−a<X<a)= 0.9
a= 0.9
In the given question the limits are -a to a . When we apply these in the above instead of [a,b] we get the above answer.
Check the picture below.
notice the midpoint of the diameter segment, is just 1,9.
also, recall the radius is half the diameter, notice how long the radius is, just 4 units.
notice the midpoint of the diameter segment, is just 1,9.
also, recall the radius is half the diameter, notice how long the radius is, just 4 units.
Answer:
I don't know the two coordinates but this would be the graph according to your equation.
Step-by-step explanation:
