<h2>
Answer:</h2>
<u><em>I believe the answer is C. </em></u>
<h2>
Explanation:</h2>
<em>I was looking at examples of adjusting entry and C was the closest one that made more sense. If I am incorrect please correct me. Hope this somehow helped and have a good one!</em>
<h2>
✍(◔◡◔)</h2>
Answer:
The answer is A) $488 000
Explanation:
The current carrying amount of the batting cage is $30 000 ( 225000 - 195000 ). Although the cage is only being traded in for $12000. The $18000 is regarded as loss to the company trading in the batting cage.
The value of the boot is therefore the amount of batting cage acquired less the trade in value of $ 18000. We thus get to an amount of $ 488000
Answer:
(a)The implied cost of shortage per quart is = $4.75
(b) This could be viewed as reasonable figure, because is (approximately) equal to the loss per quart of strawberry.
Explanation:
Solution
Given that:
Mean =μ = 40
Standard deviation =σ = 6
Excess cost= Ce =$0.35
The amount ordered =S₀= 49
Thus
Z =(49 -40)/6
=1.5
Now
From the Table Z, we have the service level which is,
P(X <49 ) = P(Z < 1.5)
= 0.9332
Since we know that,
Service level (SL) =Cs/Cs+Ce
So,
0,9332 =Cs/Cs+0.35
Thus
0.9332Cs + 0.35* 0.9332 =Cs
0.0668Cs =0.32662
Hence
Cs = $4.75
(a) The implied cost of shortage per quart is = $4.75
(b) Therefore,this could be regarded as reasonable figure, because is (approximately) equal to the loss per quart of strawberry.
This is binomial
distribution problem. <span>
We are given that:</span>
n = sample size = 500
p = proportion which
burns wood = 0.27,
q = proportion which
does not burn wood = 1-p = 0.73
<span>
A. Mean is calculated as:</span>
Mean = n*p
Mean = 500 * 0.27
Mean = 135
<span>
B. Variance is calculated as:</span>
Variance = n*p*q
Variance = 500*0.27*0.73
Variance = 98.55
<span>
C. Standard deviation is calculated as:</span>
Standard deviation = sqrt(variance)
Standard deviation =
sqrt(98.55)
<span>Standard deviation =
9.93</span>
