Using the normal distribution, it is found that Sue will get a letter grade of B.
In a <em>normal distribution </em>with mean
and standard deviation
, the z-score of a measure X is given by:

- It measures how many standard deviations the measure is from the mean.
- After finding the z-score, we look at the z-score table and find the p-value associated with this z-score, which is the percentile of X.
In this problem, Sue got a grade of 0.85, hence
.
- Looking at the z-table, z = 0.85 has a p-value of 0.8023, hence she is approximately in the top 20%, which is below the top 15% but above the top 50%, hence she got a letter grade of B.
A similar problem is given at brainly.com/question/25745464
.21 as a fraction would be 21/100
Answer:
c hope this helps
Step-by-step explanation:
Answer:
-60 miles per hour
Step-by-step explanation:
Only like sedans: 25- 15 = 10
Only like hatchbacks: 40-15 = 25
Like both: 15
Like none of them: 100-10-25-15 = 50
Dislike sedans: 100 - 10-15 = 75
Dislike hatchbacks: 100-25-15 = 60
So dislikes: sedans>hatchbacks