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2 years ago

5

Austin Avenue Accessories borrowed $14,000 for 3 years at a simple interest rate of 6.6%. The interest is to be paid semiannuall

y.
(A) Find the amount of the semiannual interest payment.
(B) Find the total interest paid

1 answer:

Anna71 [15]2 years ago

5 0

B would be the correct answer! Have a good day!

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Subtract-5 from the additive inverse of 4

gavmur [86]

Answer:

-9

Step-by-step explanation:

The additive inverse of 4 is -4. Why? 4 + -4 = 0

-4 - 5 = -9

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Which of the following is the graph of y = negative StartRoot x EndRoot + 1? On a coordinate plane, an absolute value curve curv

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Answer:

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Correct answer choice is B

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You have 480 roses and 24 of them dies, how many per cent died?

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5%

Step-by-step explanation:

5% of the roses died.

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To find the percent of roses that died, we take the number of roses that died and divide it by the total amount of roses there are and multiply it by 100 to find the percent.

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3 years ago

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1. if csc β = 7/3 and cot β = - 2√10 / 3, Find sec β

slava [35]

Step-by-step explanation:

1.

$\tan \beta = \frac{1}{ \cot \beta } = - \frac{3}{2 \sqrt{10} } = - \frac{3 \sqrt{10} }{20}$

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Therefore,

$\sec \beta = ( \frac{7}{3} )( - \frac{3 \sqrt{10} }{20} ) = - \frac{7 \sqrt{10} }{20}$

2.

$\csc y = \frac{1}{ \sin y} = - \frac{ \sqrt{6} }{2}$

$= > \sin y = - \frac{ \sqrt{6} }{3}$

Use the identity

$\cos y = \sqrt{1 - \sin ^{2} y} \: \: \: \: \: \: \: \: \: \: \: \\ = \sqrt{1 - {( - \frac{ \sqrt{6} }{3}) }^{2} } = - \frac{ \sqrt{3} }{3}$

We chose the negative value of the cosine because of the condition where cot y > 0. Otherwise, choosing the positive root will yield a negative cotangent value. Now that we know the sine and cosine of y, we can now solve for the tangent:

$\tan \beta = \frac{ \sin y}{ \cos y} =( - \frac{ \sqrt{6} }{3} )( - \frac{3}{ \sqrt{3} } ) = \sqrt{2}$

3. Recall that sec x = 1/cos x, therefore cos x = 5/6. Solving for sin x,

$\sin x = \sqrt{1 - \cos ^{2} x} = \sqrt{ \frac{11}{6} }$

Solving for tan x:

$\tan x = \frac{ \sin x}{ \cos x} = (\frac{ \sqrt{11} }{ \sqrt{6} } )( \frac{6}{5} ) = \frac{ \sqrt{66} }{5}$

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