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noname [10]
3 years ago
14

Write the recursive rule and the iterative rule for the following sequence: 10, 6, 2, -2, -6

Mathematics
1 answer:
barxatty [35]3 years ago
7 0
The recursive rule is
a_n=a_{n-1}+(-4). 
The iterative rule is
a_n=14-4n

The recursive rule is given by the formula 
a_n=a_{n-1}+d, where d is the common difference.  Our common difference is -4, which gives us the recursive rule above.

The iterative rule begins with the formula
a_n=a_1+d(n-1), where a₁ is the first term and d is the common difference.  Our first term is 10 and our common difference is -4:
a_n=10+(-4)(n-1)
\\\text{Using the Distributive Property,}
\\
\\a_n=10+(-4*n)+(-4*-1)
\\
\\a_n=10-4n+4
\\
\\\text{Combining like terms,}
\\
\\a_n=14-4n
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Answer:

15 ft

Step-by-step explanation:

Hi, the illustration for the problem is a right triangle with:

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horizontal side(A) = distance from bottom of the ladder to the building = L - 6

vertical side(B) = distance from the top of the ladder to the bottom of the building = L - 3

So, we can use Pythagoras formula:

A2 +B2= C2

(L – 6 )² + (L-3)² = L²

L²-12L+36+L²-6L+9 =L²

L2 -18L+45 =0

APPLYING QUADRATIC FORMULA WE OBTAIN:

L =15 OR L=3

If L=3

Vertical side = L-3 = 0 (Length can´t be 0)

So L=15

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3 years ago
Bhaskar went for hiking with scouts’ team and there the scouts were given a task to build tents with the help of bamboos, ropes
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The triangles on Bhaskar's tent are similar triangles.  

  • <em>The length of IJ is 4.5 m </em>
  • <em>The applicable theorem is the mid-point theorem </em>
  • <em>The appropriate formula for area is the Heron's formula </em>
  • <em>The ratio of ABC to DEF is 1 : 9</em>

<u>(a) The length of IJ</u>

The given parameter are:

\mathbf{EF = 9m}

I and J are at the midpoint of DE and DF

The above highlight means that

\mathbf{IJ= \frac 12 \times EF} --- midpoint theorem

Substitute 9 for EF

\mathbf{IJ= \frac 12 \times 9m}

\mathbf{IJ= 4.5\ m}

<u>(b) The property used to find GH and IJ</u>

In (a), the midpoint theorem is used to calculate IJ

GH and IJ are corresponding sides of similar triangles,

So the midpoint theorem can also be used to calculate the length of GH

<u>(c) The area of the triangle</u>

For the given triangles, the lengths of the sides are known.

When side lengths are known, the formula to use for finding the triangle's area is the Heron's formula.

The Heron's formula is:

\mathbf{Area = \sqrt{s \times (s -a) \times (s - b) \times (s - c)}}

Where:

\mathbf{s = a + b + c}\\\mathbf{a,b,c \to sides\ of\ the\ triangle}

<u>(d): The ratio of the areas:</u>

For the small triangle, we have:

\mathbf{a= 3.8,\ b = 4,\ c = 3}

So, we have:

\mathbf{s = 3.8 + 4 + 3 = 10.8}

So, the area is:

\mathbf{Area = \sqrt{s \times (s -a) \times (s - b) \times (s - c)}}

\mathbf{A_{small} = \sqrt{10.8 \times (10.8 -3.8) \times (10.8 - 4) \times (10.8 - 3)}}

\mathbf{A_{small} = \sqrt{4009.824}}

For the big triangle, we have:

\mathbf{a= 11.4,\ b = 12,\ c = 9}

So, we have:

\mathbf{s = 11.4 + 12 + 9 = 32.4}

So, the area is:

\mathbf{Area = \sqrt{s \times (s -a) \times (s - b) \times (s - c)}}

\mathbf{A_{big} = \sqrt{32.4 \times (32.4 -11.4) \times (32.4 - 12) \times (32.4 - 9)}}

\mathbf{A_{big} = \sqrt{324795.744}}

The ratio of the small triangle to the big triangle is:

\mathbf{Ratio = A_{small} : A_{big}}

\mathbf{Ratio = \sqrt{4009.824}:\sqrt{324795.744}}

Divide by 4009.824

\mathbf{Ratio = \sqrt{1}:\sqrt{81}}

Take square roots

\mathbf{Ratio = 1 : 9}

Hence, the ratio of ABC to DEF is 1 : 9

Read more about similar triangles at:

brainly.com/question/24874611

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V = 4/3π(2 ft)³
V = 33.51 ft³
The 9 spheres will have a total volume of 301/59 ft³ which is also equal to 521152.52 in³.
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