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grandymaker [24]
2 years ago
5

Planes A and B intersect.

Mathematics
1 answer:
balandron [24]2 years ago
8 0

Answer: point X

Step-by-step explanation:

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In the figure, assume that angles that appear to be right angles are right angles.
Kaylis [27]

Answer:

45

Step-by-step explanation:

split the shape in three parts, 3*5 + 6*4 + 3*4/2

4 0
2 years ago
Solve the equation<br> -3x + 1 + 10x = x + 4<br> 0 x = 1/2<br> х<br> =<br> x = 12<br> X = 18
pav-90 [236]

Answer:

<h3>            x = 1/2</h3>

Step-by-step explanation:

-3x + 1 + 10x = x + 4

      -1                  -1

        7x  = x  + 3  

       -x          -x

        6x = 3

      ÷6      ÷6

         x = 1/2

8 0
3 years ago
Could somebody help me with this please? i forgot how to do these.
goblinko [34]
Since a full circle has 360degrees and this circle only has two angles, subtract the arc of the known angle to find the arc of the unknown angle.

Angle DGF + angle DEF= 360degrees

Angle DGF + 70degrees= 360 degrees

Angle DGF = 290 degrees

The arc of the unknown angle is 290 degrees
4 0
4 years ago
Suppose that v is an eigenvector of matrix A with eigenvalue λA, and it is also an eigenvector of matrix B with eigenvalue λB. (
galben [10]

Answer:

(a) Yes, λ_{A}+λ_{B}

(b) Yes, λ_{A}λ_{B}

Step-by-step explanation:

First, lets understand what are eigenvectors and eigenvalues?

Note: I am using the notation λ_{A} to denote Lambda(A) sign.

v is an eigenvector of matrix A with eigenvalue λ_{A}

v is also eigenvector of matrix B with eigenvalue λ_{B}

So we can write this in equation form as

Av=λ_{A}v

So what does this equation say?

When you multiply any vector by A they do change their direction. any vector  that is in the same direction as of Av, then this v  is called the eigenvector of A. Av is λ_{A} times the original v. The number λ_{A} is the eigenvalue of A.

λ_{A} this number is very important and tells us what is happening when we multiply Av. Is it shrinking or expanding or reversed or something else?

It tells us everything we need to know!

Bonus:

By the way you can find out the eigenvalue of Av by using the following equation:

det(A-λI)=0

where I is identity matrix of the size of same as A.

Now lets come to the solution!

(a) Show that v is an eigenvector of A + B and find its associated eigenvalue.

The eigenvalues of A and B are λ_{A} and λ_{B}, then

(A+B)(v)=Av+Bv=(λ_{A})v + (λ_{B})v=(λ_{A}+λ_{B})(v)

so,  (A+B)(v)=(λ_{A}+λ_{B})(v)

which means that v is also an eigenvector of A+B and the associated eigenvalues are λ_{A}+λ_{B}

(b) Show that v is an eigenvector of AB and find its associated eigenvalue.

The eigenvalues of A and B are λ_{A} and λ_{B}, then

(AB)(v)=A(Bv)=A(λ_{B})=λ_{B}(Av)=λ_{B}λ_{A}(v)=λ_{A}λ_{B}(v)

so,  

(AB)(v)=λ_{A}λ_{B}(v)

which means that v is also an eigenvector of AB and the associated eigenvalues are λ_{A}λ_{B}

5 0
3 years ago
Find g(x)+ h(x)<br> g(x)= 3- 2x + 2x2<br> h(x)= 4x - 5 + 3x2
KIM [24]

Step-by-step explanation:

put the values of g(x) and h(x) and collect the like terms and solve them

8 0
3 years ago
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