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stellarik [79]
3 years ago
12

Could somebody help me with this please? i forgot how to do these.

Mathematics
1 answer:
goblinko [34]3 years ago
4 0
Since a full circle has 360degrees and this circle only has two angles, subtract the arc of the known angle to find the arc of the unknown angle.

Angle DGF + angle DEF= 360degrees

Angle DGF + 70degrees= 360 degrees

Angle DGF = 290 degrees

The arc of the unknown angle is 290 degrees
You might be interested in
You have $700 to invest in an account and need to have $950 in one year. What interest rate would you need to have in order to r
zhenek [66]

Answer:

136% = 1.36

Step-by-step explanation:

(950-700)/700

=0.3571 (0.36)

Then you have to plus one

0.36+1

=136% or 1.36

4 0
3 years ago
Which statement describes the inverse of m(x) = x2 – 17x?
stealth61 [152]

Answer:

The correct option is;

The \ domain \ restriction \ x \geq \dfrac{17}{2} \ results \ in \ m^{-1}(x) = \dfrac{17}{2} \pm \sqrt{x + \dfrac{289}{4} }}

Step-by-step explanation:

The given information is that m(x) = x² - 17·x

The above equation can be written in the form;

y = x² - 17·x

Therefore;

0 = x² - 17·x - y

From the general solution of a quadratic equation, 0 = a·x² + b·x + c we have;

x = \dfrac{-b\pm \sqrt{b^{2}-4\cdot a\cdot c}}{2\cdot a}

By comparison to the equation,0 = x² - 17·x - y, we have;

a = 1, b = -17, and c = -y

Substituting the values of a, b and c into the formula for the general solution of a quadratic equation, we have;

x = \dfrac{-(-17)\pm \sqrt{(-17)^{2}-4\times (1) \times (-y)}}{2\times (1)} = \dfrac{17\pm \sqrt{289+4\cdot y}}{2}

Which can be simplified as follows;

x =  \dfrac{17\pm \sqrt{289+4\cdot y}}{2}= \dfrac{17}{2} \pm \dfrac{1}{2}  \times \sqrt{289+4\cdot y}} = \dfrac{17}{2} \pm \sqrt{\dfrac{289}{4} +\dfrac{4\cdot y}{4} }}

And further simplified as follows;

x = \dfrac{17}{2} \pm \sqrt{\dfrac{289}{4} +y }} = \dfrac{17}{2} \pm \sqrt{y + \dfrac{289}{4} }}

Interchanging x and y in the function of the inverse, m⁻¹(x), we have;

m^{-1}(x) = \dfrac{17}{2} \pm \sqrt{x + \dfrac{289}{4} }}

We note that the maximum or minimum point of the function, m(x) = x² - 17·x found by differentiating the function and equating the result to zero, gives;

m'(x) = 2·x - 17 = 0

x = 17/2

Similarly, the second derivative is taken to determine if the given point is a maximum or minimum point as follows;

m''(x) = 2 > 0, therefore, the point is a minimum point on the graph

Therefore, as x increases past the minimum point of 17/2, m⁻¹(x) increases to give;

The \ domain \ restriction \ x \geq \dfrac{17}{2} \ results \ in \ m^{-1}(x) = \dfrac{17}{2} \pm \sqrt{x + \dfrac{289}{4} }} to increase m⁻¹(x) above the minimum.

8 0
3 years ago
Hii please help i’ll give brainliest
yaroslaw [1]

Answer: Point K

Step-by-step explanation:

The first number is the x line and the second number is the y line <3  pls mark brainliest

5 0
3 years ago
Graph the relation. Is the relation a function? Why or why not? {(–5, 6), (–2, 3), (3, 2), (6, 4)} No; a domain value has two ra
RoseWind [281]

Answer:

Yes; there is only one range value for each domain value

Step-by-step explanation:

A relation can be defined as a function f(x) if for each value of the domain of x, there exists a unique value of f(x).

For example

(2, 4)(3, 9)(-2, 4)(4, 16) Is a Function

(2, 4)(2,6)(3, 8)(3, -8) Is Not a Function

To analyze if the relationship shown is a function, you must observe that each value of the domain has a single value of the range assigned.

For the given points {(-5, 6), (-2, 3), (3, 2), (6, 4)} this requirement is satisfied. Therefore, the relationship is a function. The graph is shown in the attached image.

The correct option is: Yes; there is only one range value for each domain value

4 0
3 years ago
Read 2 more answers
Calculate the surface area of the box<br><br> 6.5 inches by 6 inches by 2 inches
hram777 [196]
The answer is 60.50 DO THE MATH LAZY!!!!!!!
5 0
3 years ago
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