P = how many cars Peter has
j = how many cars Jade has
a = how many cars Andre has
p x 4 = how many cars Andre has (36 model cars)
>>>TO FIND HOW MANY MODEL CARS PETER HAS:
p x 4 = 36
36 / 4 = 9
your equation to find how many model cars Peter has is:
36 / 4 = 9
So, Peter has 9 model cars.
>>>TO FIND HOW MANY MODEL CARS JADE HAS:
36 / 4 = how many cars Peter has (9)
Now, you are given the info that Jade has THREE TIMES (3x) as many cars as Peter already.
So, your equation for this one is:
9 x 3 = 27
So Jade has 27 model cars.
---- Jade has 27 model cars.
---- Andre has 36 model cars.
---- Peter has 9 model cars.
equation for a. 36 / 4 = p
equation for b. 9 x 3 = j
What can u send o pic of assignment
Answer:
Step-by-step explanation:
If the profit realized by the company is modelled by the equation
P (x) = −0.5x² + 120x + 2000, marginal profit occurs at dP/dx = 0
dP/dx = -x+120
P'(x) = -x+120
Company's marginal profit at the $100,000 advertising level will be expressed as;
P '(100) = -100+120
P'(100) = 20
Marginal profit at the $100,000 advertising level is $20,000
Company's marginal profit at the $140,000 advertising level will be expressed as;
P '(140) = -140+120
P'(140) = -20
Marginal profit at the $140,000 advertising level is $-20,000
<u>Based on the marginal profit at both advertising level, I will recommend the advertising expenditure when profit between $0 and $119 is made. At any marginal profit from $120 and above, it is not advisable for the company to advertise because they will fall into a negative marginal profit which is invariably a loss.</u>
The answer is Isosceles triangle
A got the most votes because the ration works with the percentage very well
