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3 years ago

In a circle with a radius of 3 ft, an arc is intercepted by a central angle of 2π3 radians. What is the length of the arc?

2 answers:

5 0

The correct question is
<span>In a circle with a radius of 3 ft, an arc is intercepted by a central angle of 2π/3 radians. What is the length of the arc?

we know that
in a circle
</span>2π radians -----------------> lenght of (2*π*r)
2π/3 radians--------------> X
X=[(2π/3)*(2π*r)]/[2π]=(2π/3)*r

the lenght of the arc=(2π/3)*3=2π ft

the answer is 2π ft

Musya8 [376]3 years ago

4 0

Answer: 2 π I just took the test

Step-by-step explanation:

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3 years ago

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Step-by-step explanation:

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1 year ago

Tan(-212°)=____.<br><br> 1. -cot 32°<br> 2. tan 32°<br> 3. cot 32°<br> 4. -tan 32°

Marrrta [24]

Answer:

4. $-\tan 32$ °

Step-by-step explanation:

Given:

The tangent of the angle is given as:

$\tan (-212\°)$

Since the angle is negative, it means that it is measured in the clockwise direction as angles measured in clockwise direction are negative and that measured in counter clockwise directions are positive.

-212° when measured from counter clockwise direction will be equal to:

$-212\°(Clockwise)=360-212=148\°(CCW)$

Therefore, $\tan (-212\°)$ = $\tan (148\°)$

Now, we have the identity for tan as:

$\tan(\pi-\theta)=-\tan \theta$

Here, $\theta=148\°$

Therefore,

$-\tan (148\°)=\tan(180-148)\\-\tan(148\°)=\tan(32\°)\\\textrm{Multiplying both sides by -1, we get:}\\-1(-\tan(148\°)=-1\times \tan(32\°)\\\\\tan(148\°)=-\tan(32\°)$

Hence, $\tan (-212\°)$ = $\tan (148\°)$ = $-\tan 32$ °

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3 years ago