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Alexus [3.1K]
3 years ago
15

24 pencils costing a total of $3.00 how many cents per a pencil

Mathematics
2 answers:
Mkey [24]3 years ago
7 0

Answer:

The pencils cost about 13 cents a pencil.

Step-by-step explanation:

Divide 3 by 24 and you get 0.125 you can round to the nearest hundredth to get 13 cents. Also see if 12 cents is a answer if 13 cents is not available.

hram777 [196]3 years ago
3 0

Answer:

$0.125 , so 12.5 cents per pencil

Step-by-step explanation:

\frac{3.00}{24}

You can double check this by doing 0.125*24 , making sure it equals 3.

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-----------------------------\\\\
\textit{using the disc method}
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V=\int\limits_{0}^{6}\pi \left[ sin\left( \frac{\pi x}{6} \right) \right]^2\cdot dx\implies \pi\int\limits_{0}^{6} \left[ sin\left( \frac{\pi x}{6} \right) \right]^2\cdot dx
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\bf \textit{now, let us check the double angle identities}
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cos(2\theta)=
\begin{cases}
cos^2(\theta)-sin^2(\theta)\\
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\bf \pi\int\limits_{0}^{6} \left[ sin\left( \frac{\pi x}{6} \right) \right]^2\cdot dx\implies 
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and surely, you'd know how to get the values for the bounds there

5 0
3 years ago
At a certain pizza parlor, % of the customers order a pizza containing onions, % of the customer's order a pizza containing saus
wel

Answer:

At a certain pizza parlor,36 % of the customers order a pizza containing onions,35 % of the customers order a pizza containing sausage, and 66% order a pizza containing onions or sausage (or both). Find the probability that a customer chosen at random will order a pizza containing both onions and sausage.

Step-by-step explanation:

Hello!

You have the following possible pizza orders:

Onion ⇒ P(on)= 0.36

Sausage ⇒ P(sa)= 0.35

Onions and Sausages ⇒ P(on∪sa)= 0.66

The events "onion" and "sausage" are not mutually exclusive, since you can order a pizza with both toppings.

If two events are not mutually exclusive, you know that:

P(A∪B)= P(A)+P(B)-P(A∩B)

Using the given information you can use that property to calculate the probability of a customer ordering a pizza with onions and sausage:

P(on∪sa)= P(on)+P(sa)-P(on∩sa)

P(on∪sa)+P(on∩sa)= P(on)+P(sa)

P(on∩sa)= P(on)+P(sa)-P(on∪sa)

P(on∩sa)= 0.36+0.35-0.66= 0.05

I hope it helps!

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3 years ago
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IgorC [24]

Answer:

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Step-by-step explanation:

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2 years ago
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