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Anon25 [30]
2 years ago
10

Please help me..asap

Mathematics
1 answer:
Ivenika [448]2 years ago
6 0

Answer:

D

the first one obviously isnt random
the second one is selective then random
the third one is also selective
the fourth one is random

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Plz help..................refresh page before u answer
Ksenya-84 [330]
The answer is the first one 6/7ab
5 0
3 years ago
For the linear model, y = -67.9x + 679 , the distance, in miles y, is a function of time, x, in hours. Use the model to calculat
Ksenya-84 [330]

Answer:

339.5

Step-by-step explanation:

-67.9x+679= y

-67.9*5+679=

-339.5+679= 339.5

4 0
2 years ago
<img src="https://tex.z-dn.net/?f=2m%20-%20%28m%20%2B%201%29%20%3D%200" id="TexFormula1" title="2m - (m + 1) = 0" alt="2m - (m +
natali 33 [55]

Answer: ..........................................................................................................................................................................................................................................................

8 0
3 years ago
2+2=4-1=3 2+4+4+5+6+1+8=
Vinvika [58]

Answer:

30

Step-by-step explanation:

8 0
2 years ago
Read 2 more answers
Verify the identity. 4 csc 2x = 2 csc2x tan x
vlada-n [284]

Step-by-step explanation:

4csc(2x) = 2csc^2(x) tan(x)

We start with Left hand side

We know that csc(x) = 1/ sin(x)

So csc(2x) is replaced by 1/sin(2x)

4 \frac{1}{sin(2x)}

Also we use identity

sin(2x) = 2 sin(x) cos(x)

4 \frac{1}{2sin(x)cos(x)}

4 divide by 2 is 2

Now we multiply top and bottom by sin(x) because we need tan(x) in our answer

2\frac{1*sin(x)}{sin(x)cos(x)*sin(x)}

2\frac{sin(x)}{sin^2(x)cos(x)}

2\frac{1}{sin^2(x)} \frac{sin(x)}{cos(x)}

We know that sinx/ cosx = tan(x)

Also  1/ sin(x)= csc(x)

so it becomes 2csc^2(x) tan(x) , Right hand side

Hence verified



6 0
3 years ago
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