Hi!
So for this problem, we're given the y-coordinate and we can plug that in for y in the equation. So let's do that
-1 = -3/5x - 7
6 = -3/5x
30 = -3x
-10 = x
The missing coordinate would be x, assuming that the equation was y = (-3/5)x - 7
The work done in pushing the box is 64000 lb-ft²/s²
<h3>How to calculate the work done by the person?</h3>
Since person pushing a 40 pound box up an incline that is 30 degrees above the horizontal and 100 feet long, the work done, W is
W = mgh where
- m = mass of box = 40 lb,
- g = acceleration due to gravity = 32 ft/s² and
- h = height of incline = LsinФ where
- L = length of incline = 100 ft and
- Ф = angle of incline = 30°
So, W = mgh
W = mgLsinФ
So, substituting the values of the variables into the equation, we have
W = mgLsinФ
W = 40 lb × 32 ft/s² × 100 ftsin30°
W = 1280 lb-ft/s² × 100 ft × 0.5
W = 1280 lb-ft/s² × 50 ft
W = 64000 lb-ft²/s²
So, the work done in pushing the box is 64000 lb-ft²/s²
Learn more about work done here:
brainly.com/question/25970931
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Answer:
x= 10, x=1
Step-by-step explanation:
(x-1)(x-10)=0
then solve for x
Answer:
Water left in tank is 
gallons.
Step-by-step explanation:
Given :
Capacity of tank = 9.5 gallons 
Water taken out of tank =
gallons
We have to find the water left in the tank.
Water left in the tank = Total capacity of tank - water taken out of tank
=
Taking LCM of (3,10)= 30
Solving further, we get,
Thus, Water left in tank is gallons..
