The square roots of 64 is A B and C.
Okay, you would need to distribute it.
It would be 3/4x - 3/4 = 10/8x - 20/8
Answer:
For first lamp ; The resultant probability is 0.703
For both lamps; The resultant probability is 0.3614
Step-by-step explanation:
Let X be the lifetime hours of two bulbs
X∼exp(1/1400)
f(x)=1/1400e−1/1400x
P(X<x)=1−e−1/1400x
X∼exp(1/1400)
f(x)=1/1400 e−1/1400x
P(X<x)=1−e−1/1400x
The probability that both of the lamp bulbs fail within 1700 hours is calculated below,
P(X≤1700)=1−e−1/1400×1700
=1−e−1.21=0.703
The resultant probability is 0.703
Let Y be a lifetime of another lamp two bulbs
Then the Z = X + Y will follow gamma distribution that is,
X+Y=Z∼gamma(2,1/1400)
2λZ∼
X+Y=Z∼gamma(2,1/1400)
2λZ∼χ2α2
The probability that both of the lamp bulbs fail within a total of 1700 hours is calculated below,
P(Z≤1700)=P(1/700Z≤1.67)=
P(χ24≤1.67)=0.3614
The resultant probability is 0.3614
Answer:
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Answer:
Step-by-step explanation:
square = 468 m² x² + (6+x)² = 468 [Area of a square = side²] x² + (6)² + x² + 2×6×x= 468 [(a+b)²= a²+b²+2ab] 2x² + 36 + 12x= 468 2x² + 12x + 36 - 468= 0 2x² + 12x + 36 - 432 = 0 2(x² +6x - 216)= 0 x² +6x - 216 = 0 x² +18x -12x -216 =0