1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
trasher [3.6K]
2 years ago
12

How many more tons does a blue whale weigh than an African elephant

Mathematics
1 answer:
lapo4ka [179]2 years ago
8 0
A blue whale weight = 200 short tons (400,000 pounds)
A african elephant weight = 3 tons (9,000 pounds)
And then you would minus the tons and get your answer 
hope this helped :)
You might be interested in
EXAMPLE 5 Find the maximum value of the function f(x, y, z) = x + 2y + 11z on the curve of intersection of the plane x − y + z =
Taya2010 [7]

Answer:

\displaystyle x= -\frac{10}{\sqrt{269}}\\\\\displaystyle y= \frac{13}{\sqrt{269}}\\\\\displaystyle z = \frac{23\sqrt{269}+269}{269}

<em>Maximum value of f=2.41</em>

Step-by-step explanation:

<u>Lagrange Multipliers</u>

It's a method to optimize (maximize or minimize) functions of more than one variable subject to equality restrictions.

Given a function of three variables f(x,y,z) and a restriction in the form of an equality g(x,y,z)=0, then we are interested in finding the values of x,y,z where both gradients are parallel, i.e.

\bigtriangledown  f=\lambda \bigtriangledown  g

for some scalar \lambda called the Lagrange multiplier.

For more than one restriction, say g(x,y,z)=0 and h(x,y,z)=0, the Lagrange condition is

\bigtriangledown  f=\lambda \bigtriangledown  g+\mu \bigtriangledown  h

The gradient of f is

\bigtriangledown  f=

Considering each variable as independent we have three equations right from the Lagrange condition, plus one for each restriction, to form a 5x5 system of equations in x,y,z,\lambda,\mu.

We have

f(x, y, z) = x + 2y + 11z\\g(x, y, z) = x - y + z -1=0\\h(x, y, z) = x^2 + y^2 -1= 0

Let's compute the partial derivatives

f_x=1\ ,f_y=2\ ,f_z=11\ \\g_x=1\ ,g_y=-1\ ,g_z=1\\h_x=2x\ ,h_y=2y\ ,h_z=0

The Lagrange condition leads to

1=\lambda (1)+\mu (2x)\\2=\lambda (-1)+\mu (2y)\\11=\lambda (1)+\mu (0)

Operating and simplifying

1=\lambda+2x\mu\\2=-\lambda +2y\mu \\\lambda=11

Replacing the value of \lambda in the two first equations, we get

1=11+2x\mu\\2=-11 +2y\mu

From the first equation

\displaystyle 2\mu=\frac{-10}{x}

Replacing into the second

\displaystyle 13=y\frac{-10}{x}

Or, equivalently

13x=-10y

Squaring

169x^2=100y^2

To solve, we use the restriction h

x^2 + y^2 = 1

Multiplying by 100

100x^2 + 100y^2 = 100

Replacing the above condition

100x^2 + 169x^2 = 100

Solving for x

\displaystyle x=\pm \frac{10}{\sqrt{269}}

We compute the values of y by solving

13x=-10y

\displaystyle y=-\frac{13x}{10}

For

\displaystyle x= \frac{10}{\sqrt{269}}

\displaystyle y= -\frac{13}{\sqrt{269}}

And for

\displaystyle x= -\frac{10}{\sqrt{269}}

\displaystyle y= \frac{13}{\sqrt{269}}

Finally, we get z using the other restriction

x - y + z = 1

Or:

z = 1-x+y

The first solution yields to

\displaystyle z = 1-\frac{10}{\sqrt{269}}-\frac{13}{\sqrt{269}}

\displaystyle z = \frac{-23\sqrt{269}+269}{269}

And the second solution gives us

\displaystyle z = 1+\frac{10}{\sqrt{269}}+\frac{13}{\sqrt{269}}

\displaystyle z = \frac{23\sqrt{269}+269}{269}

Complete first solution:

\displaystyle x= \frac{10}{\sqrt{269}}\\\\\displaystyle y= -\frac{13}{\sqrt{269}}\\\\\displaystyle z = \frac{-23\sqrt{269}+269}{269}

Replacing into f, we get

f(x,y,z)=-0.4

Complete second solution:

\displaystyle x= -\frac{10}{\sqrt{269}}\\\\\displaystyle y= \frac{13}{\sqrt{269}}\\\\\displaystyle z = \frac{23\sqrt{269}+269}{269}

Replacing into f, we get

f(x,y,z)=2.4

The second solution maximizes f to 2.4

5 0
3 years ago
Jack maclean has entered into real estate
OverLord2011 [107]

Answer:

im sorry but id ont know

Step-by-step explanation:

4 0
3 years ago
If sin ? = 12 over 37, use the pythagorean identity to find cos ?. cos ? = ± 35 over 37 cos ? = ± 23 over 37 cos ? = ± 35 over 1
kotegsom [21]
If sin x = 12/37, we have to find cos x.
The identity:
sin² x + cos² x = 1
( 12/37)² + cos² x = 1
144 / 1369 + cos² x = 1
cos² x = 1 - 144/1369
cos² x = 1369/1369  - 144/1369
cos² x = 1225 / 1369
cos x = +/- √ 1225/1369 = +/- 35/37
Answer:
A ) cos ? = +/- 35 over 37
7 0
2 years ago
Read 2 more answers
Jina is mailing packages. Each small package costs her to send. Each large package costs her . How much will it cost her to send
Novosadov [1.4K]
You need to tell me how many large and small packages she’s sending and how much each costs
8 0
3 years ago
Help ASAP PLZ HELP ME​
Gelneren [198K]

Answer:

Step-by-step explanation:

the sum of angles of triangle=180 degrees

one angle=90 degrees

180-90=90 degrees is the measure of the other two angles

since the two angles are congruent or equal

90/2=45 degrees

the measure of the 2 angles =45 degrees each

6 0
3 years ago
Other questions:
  • There are twice as many dimes as there are quarters, and twice as many nickels as there are dimes. The total amount of money is
    7·1 answer
  • Dr. Potter provides vaccinations against polio and measles. Each polio vaccination consists of 444 doses, and each measles vacci
    8·1 answer
  • In mr. Klein's class, 40% of the students are boys. What decimal represents the portion of the students that are girls
    7·2 answers
  • Write an equation in slope-intercept form for the line shown.
    8·1 answer
  • A theater group made appearances in two cities. The hotel charge before tax in the second city was $ 500 lower than in the first
    7·1 answer
  • 15 less than a number g is equal to 45
    9·2 answers
  • a family pass to the amusement park costs $54.using the distributive property , write an expression that can be used to find the
    15·2 answers
  • 3. Jim bought a new pair of glasses. The lenses had six sides. The lenses were in the shape of a A. hexagon. B. heptagon. C. qua
    10·1 answer
  • G(x) = sqr root of x+3<br><br> What is the domain of g?
    15·2 answers
  • Help me, I’ll give you brainliest. :)
    12·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!