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3 years ago

How many more tons does a blue whale weigh than an African elephant

1 answer:

8 0

A blue whale weight = 200 short tons (400,000 pounds)
A african elephant weight = 3 tons (9,000 pounds)
And then you would minus the tons and get your answer
hope this helped :)

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Question is on the photo pls help

Bond [772]

Answer:

d)-8

Step-by-step explanation:

-6s-¹t²
-6(3)-¹(-2)²
-6(⅓)(4)
-8

4 0

3 years ago

Find the area of the region enclosed by the graphs of the functions

Vaselesa [24]

Answer:

$\displaystyle A = \frac{8}{21}$

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

Equality Properties

Multiplication Property of Equality
Division Property of Equality
Addition Property of Equality
Subtraction Property of Equality

Algebra I

Terms/Coefficients
Functions
Function Notation
Graphing
Solving systems of equations

Calculus

Area - Integrals

Integration Rule [Reverse Power Rule]: $\displaystyle \int {x^n} \, dx = \frac{x^{n + 1}}{n + 1} + C$

Integration Rule [Fundamental Theorem of Calculus 1]: $\displaystyle \int\limits^b_a {f(x)} \, dx = F(b) - F(a)$

Integration Property [Addition/Subtraction]: $\displaystyle \int {[f(x) \pm g(x)]} \, dx = \int {f(x)} \, dx \pm \int {g(x)} \, dx$

Area of a Region Formula: $\displaystyle A = \int\limits^b_a {[f(x) - g(x)]} \, dx$

Step-by-step explanation:

*Note:

Remember that for the Area of a Region, it is top function minus bottom function.

Step 1: Define

f(x) = x²

g(x) = x⁶

Bounded (Partitioned) by x-axis

Step 2: Identify Bounds of Integration

Find where the functions intersect (x-values) to determine the bounds of integration.

Simply graph the functions to see where the functions intersect (See Graph Attachment).

Interval: [-1, 1]

Lower bound: -1

Upper Bound: 1

Step 3: Find Area of Region

Integration

Substitute in variables [Area of a Region Formula]: $\displaystyle A = \int\limits^1_{-1} {[x^2 - x^6]} \, dx$
[Area] Rewrite [Integration Property - Subtraction]: $\displaystyle A = \int\limits^1_{-1} {x^2} \, dx - \int\limits^1_{-1} {x^6} \, dx$
[Area] Integrate [Integration Rule - Reverse Power Rule]: $\displaystyle A = \frac{x^3}{3} \bigg| \limit^1_{-1} - \frac{x^7}{7} \bigg| \limit^1_{-1}$
[Area] Evaluate [Integration Rule - FTC 1]: $\displaystyle A = \frac{2}{3} - \frac{2}{7}$
[Area] Subtract: $\displaystyle A = \frac{8}{21}$

Topic: AP Calculus AB/BC (Calculus I/II)

Unit: Area Under the Curve - Area of a Region (Integration)

Book: College Calculus 10e

6 0

3 years ago

The cost of buying a small piece of land in a remote village since the year 1990 is represented by the following table . Which m

Effectus [21]

Answer:

C(t)=30+3.5t

Step-by-step explanation:

Yeah this is the answer

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3 years ago

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Brad wants to open a new savings account. He finds one that returns 3% on his investment each year.

Rufina [12.5K]

Answer:

final balance: A
initial investment: P
return rate: r

Step-by-step explanation:

The variable assigments can be anything you like. It is often helpful to use variables that will remind you what they stand for. Here, we have chosen A = amount (final balance); P = principal (initial investment); r = rate.

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3 years ago

Consider in the figure below.

ELEN [110]

⚘ Refer to the attachments!!~

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2 years ago

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