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Bumek [7]
3 years ago
6

Check if the point (-3, -5) lies on the line y= 2x -1 Plzzzzz hurry

Mathematics
1 answer:
olchik [2.2K]3 years ago
4 0

Answer:

no

Step-by-step explanation:

To determine if the point lies on the line, substitute x = - 3 into the equation and if the value obtained equals - 5 then it lies on the line.

y = 2(- 3) - 1 = - 6 - 1 = - 7 ≠ - 5

Then the point (- 3, - 5 ) is not on the line

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Change y-7=m(x-4) to standard form
Ivan

Answer:

  mx -y = 4m -7

Step-by-step explanation:

Standard form is ...

  ax +by = c

where a, b, c are mutually prime integers and a > 0.

If we assume m > 0, then we need to collect the variable terms on the right side of the equation, so the coefficient of x will be positive.

  y -7 = mx -4m . . . . eliminate parentheses

  -7 = mx -y -4m . . . . subtract y

  4m -7 = mx -y . . . . . add 4m

  mx -y = 4m -7 . . . . . . standard form

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2 years ago
The hypotenuse of a right triangle is startroot 21 endroot21 in and one leg measures 44 in. find the length of the other leg.
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3 years ago
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Answer:

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2 years ago
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Nikolay [14]
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x = <u>2 +/- √(4 + 12)</u>
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x = <u>2 +/- √(16)
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or
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