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TiliK225 [7]
3 years ago
7

Pilar wants to save $100. So far, she has saved $63. Find the length of each side of the square

Mathematics
1 answer:
svlad2 [7]3 years ago
4 0
Lol. This is a joke right?
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Graph ordered triples A(-4,7,3)
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Answer:

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Step-by-step explanation:

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3 years ago
A functionf(x) is graphed on the coordinate plane.
AleksandrR [38]

The function rule in slope-intercept form is y = -4x -2

<h3>What is a function ?</h3>

A function is defined as the mathematical statement which defines relation between a dependent variable and an independent variable.

A function f(x) is graphed on the coordinate plane.

The equation for a straight line is given by

y = mx + c

Where m is the slope and c is the intercept on y axis

The intercept on y axis is -2

c = -2

At x = 0 , y =-2

At x = -1 , y =2

m =(2 -(-2))/(-1-0)

m = -4

Therefore ,the function rule in slope-intercept form is y = -4x -2 .

To know more about Function

brainly.com/question/12431044

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3 0
2 years ago
Assignment
ipn [44]

Answer:17.1

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
How do I simplify this math problem?
mr Goodwill [35]
Basically, think of it as 3 / 1. 3√1 = 3/ 1 or 3/1 = 3 and 3√1 = 3
4 0
3 years ago
Can someone please help me solve these two problems and explain them to me? About the one with proportions though... I've always
NeTakaya

Answers:

A) -\frac{11}{4}

C) m_{1}=\frac{Fr^{2}}{G m_{2}}

Step-by-step explanation:

<u>Part 1:</u>

We have the followig equation:

\frac{x-1}{3}-\frac{x+4}{5}=\frac{4x-1}{8}

Calculating the least common multiple (l.c.m) in the denominator in the left side of the equation, being l.c.m=15:

\frac{5(x-1)-3(x+4)}{15}=\frac{4x-1}{8}

Solving for the left part of the equation:

\frac{2x-17}{15}=\frac{4x-1}{8}

Operating with cross product:

8(2x-17)=15(4x-1)

Applying the distributive property:

16x-136=60x-15

Isolating x:

x=-\frac{121}{44}

Dividing numerator and denominator by 11:

x=-\frac{11}{4} Hence, the correct option is A

<u>Part 2:</u>

We have the followig equation:

F=\frac{G m_{1} m_{2}}{r^{2}}

Operating with cross product:

Fr^{2}=G m_{1} m_{2}

Isolating m_{1}:

m_{1}=\frac{Fr^{2}}{G m_{2}} Hence, the correct option is C

5 0
4 years ago
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