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pav-90 [236]
3 years ago
11

Which expressions are equivalent to the one below? check all that apply :)

Mathematics
1 answer:
svlad2 [7]3 years ago
4 0


Since 5=15/3

5^x = (15/3)^x = 15^x / 3^3

Choices A and D


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Calculate the average rate of change over the interval 2
Morgarella [4.7K]

Answer:

Average rate of change over the interval 2<= x <= 5:

y = 3x + 5:        3

y = 3x^2 + 1:     21

y = 3^x:             78

<u />

Step-by-step explanation:

2<= x <= 5

Average rate of change over the interval 2<= x <= 5:

<u>y = 3x + 5</u>

y(5) = 3(5) + 5 = 20

y(2) = 3(2) + 5 = 11

Average rate of change = (20 - 11)/(5-2) = 9/3 = <u>3</u>

<u />

<u>y = 3x^2 + 1</u>

y(5) = 3(5^2) + 1 = 75 + 1 = 76

y(2) = 3(2^2) + 1= 13

Average rate of change = (76 - 13)/(5-2) = 63/3 = <u>21</u>

<u />

<u>y = 3^x</u>

y(5) = 3^5 = 243

y(2) = 3^2 =9

Average rate of change = (243-9)/(5-2) = 234/3 =<u> 78</u>

8 0
2 years ago
Pls help and remember to include the paranthesis
nydimaria [60]
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5 0
3 years ago
CD has endpoints C(-3, 4) and D(1, -2). Find the coordinates<br> of its midpoint.
Natalija [7]

Answer:

Midpoint (-1 , 1)

Step-by-step explanation:

Formula: (midpoint)

Let the point A(x , y) be the midpoint of CD.

x=\frac{x_c+x_D}{2} =\frac{-3+1}{2} =\frac{-2}{2} =-1

y=\frac{x_C + y_D}{2} =\frac{4+(-2)}{2} =\frac{2}{2} =1

Then

A(-1 , 1)

4 0
2 years ago
Read 2 more answers
Use the triangle formed by the vertices L(—3, 4), A(O, 5) and D(2, l). AL' A'D' is a triangle formed by using the transformation
weqwewe [10]

Answer:

figuring it out now

Step-by-step explanation:

6 0
3 years ago
A beetle is 1/5 inch wide and 2/5 inch long. How much greater is the beetle's length than its width?
Neporo4naja [7]

Answer:

2 times as long

Step-by-step explanation:

2/5 divded by 1/5 equals two

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3 years ago
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