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2 years ago

PLS HELP WILL GIVE BRAINIEST.

Mathematics

1 answer:

motikmotik2 years ago

5 0

Answer:

y=1/3x

Step-by-step explanation:

the first line is 1 and the second line is 3

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The diameter of Circle Q terminates on the circumference of the circle at (3,0) and (3,-7) . Write the equation of the circle in

Deffense [45]

Step-by-step explanation:

The center of a circle with 2 end points of a di diameter is the midpoint of the two endpoints.

The formula needed to find the minpoints is

(x,y) = (x2 + x1)/2, (y2 + y1)/2

x2 = 3

x1 = 3

y2 = 0

y1 = -7

midpoint = (3 + 3)/2, (0 - 7)/2

midp[oint = 3,-3.5

The midpoint is the center of the circle. Observe that the signs get changed when entering the values for (x,y)

So far what you have is (x - 3)^2 + (y + 3.5)^2 = r^2

To determine r^2 you need only take the distance from the center to oneof the endpoints.

r^2 = (3 - 3)^2 + (3.5 - 0)^2

r^2 = 3.5^2

r^2 = 12.25

Answer: (x - 3)^2 + (y + 3.5)^2 = 12.25

6 0

3 years ago

1.what is a sports car average acceleration if it can go from 0m/s to 27m/s in 6.0 seconds?

Flauer [41]

Answer:

1.4.5m/s^2

2.6.25m/s^2

3.15m/s^2

4.0.05m/s^2

Step-by-step explanation:

a=v-u

----

27-0

------ = 27/6

=4.5m/s^2

u=4.5m/s

v=24.5m/s

t=3.2s

(24.5-4.5)÷3.2

=20/3.2

=6.25m/s^2

v=80m/s

u=50m/s

t=2s

(80-50)÷2

15m/s^2

v=0.80m/s

u=0.50m/s

t=6s

(0.80-0.50)÷6

=0.05m/s^2

5 0

2 years ago

SUPER URGENT PLEASE ANSWER ASAP

gladu [14]

Answer:

shown below

Step-by-step explanation:

Look at the white squares, count them. 1, 2, 3. the next will be 4 and 5. draw 4 white squares, then house it in black squares like the others. to know if u did it right, count the black squares, there should be 8, then 9.

7 0

2 years ago

What is the radius of a circle with an area of 50.24 cubic inches? Use 3.14 for pi.

OverLord2011 [107]

Hope this helps you..!!!

3 0

4 years ago

Find the work (in ft-lb) required to pump all the water out of a cylinder that has a circular base of radius 7 ft and height 200

Virty [35]

Answer:

work done is equal to 384279168 lb-ft

Step-by-step explanation:

The cylinder has a circular base of 7 ft.

The height of the cylinder is 200 ft

The weight density of water in the cylinder is 62.4 lb/ft^3

First, we find the volume of the water in the cylinder by finding the volume of this cylinder occupied by the water.

The volume of a cylinder is given as $\pi r^{2} h$

where, r is the radius,

and h is the height of the cylinder.

the volume of the cylinder = $3.142* 7^{2}*200$ = 30791.6 ft^3

Since the weight density of water is 62.4 lb/ft^3, then, the weight of the water within the cylinder will be...

weight of water = 62.4 x 30791.6 = 1921395.84 lb

We know that the whole weight of the water will have to be pumped out over the height of cylindrical container. Also, we know that the work that will be done in moving this weight of water over this height will be the product of the weight of water, and the height over which it is pumped. Therefore...

The work done in pumping the water out of the container will be

==> (weight of water) x (height of cylinder) = 1921395.84 x 200

==> work done is equal to 384279168 lb-ft

7 0

3 years ago