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Thepotemich [5.8K]
3 years ago
15

Topic: Area of non shaded area.

Mathematics
2 answers:
Dimas [21]3 years ago
8 0

Answer:B) 150

Step-by-step explanation:

Area of rec= L×W

= 10×30= 300

Area of shaded area= 1/2 Base× Height

1/2×10×15=75

75×2 = 150

Area of unshaded part= 300-150= 150

gavmur [86]3 years ago
6 0

Answer:

150 Square Units

Step-by-step explanation:

(Sorry if I become confusing)

The base of the triangles is 10 units.

The height of the triangles is 15 units.

The formula I used was A=\frac{1}{2}bh

b=base and h=height A=area

A=\frac{1}{2}(10)(15)

A=\frac{1}{2}(10)(15)=75

A=75

Multiply by two to get the area for both triangles.

75·2=150

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An acute angle θ is in a right triangle with sin θ = seven eighths. What is the value of cot θ?
olga2289 [7]
Draw a right triangle ABC, with m(CAB)=∅.

Let CB=7 units, AC=8 units, so by the Pythagorean theorem:

AB= \sqrt{ AC^{2} - BC^{2} }= \sqrt{ 8^{2} - 7^{2} }=  \sqrt{64-49} = \sqrt{15} (units)

so we have drawn a triangle where sin∅=7/8

in this triangle, cot∅=(adjacent side)/(opposite side)=\frac{ \sqrt{15} }{7}

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Given that curl F = 2yi – 2zj + 3k, find the surface integral of the normal component of curl F (not F) over (a) the open hemisp
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Use Stokes' theorem for both parts, which equates the surface integral of the curl to the line integral along the surface's boundary.

a. The boundary of the hemisphere is the circle x^2+y^2=9 in the plane z=0, where the curl is \mathrm{curl}\vec F=2y\,\vec\imath+3\,\vec k. Green's theorem applies here, so that

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