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Thepotemich [5.8K]
3 years ago
15

Topic: Area of non shaded area.

Mathematics
2 answers:
Dimas [21]3 years ago
8 0

Answer:B) 150

Step-by-step explanation:

Area of rec= L×W

= 10×30= 300

Area of shaded area= 1/2 Base× Height

1/2×10×15=75

75×2 = 150

Area of unshaded part= 300-150= 150

gavmur [86]3 years ago
6 0

Answer:

150 Square Units

Step-by-step explanation:

(Sorry if I become confusing)

The base of the triangles is 10 units.

The height of the triangles is 15 units.

The formula I used was A=\frac{1}{2}bh

b=base and h=height A=area

A=\frac{1}{2}(10)(15)

A=\frac{1}{2}(10)(15)=75

A=75

Multiply by two to get the area for both triangles.

75·2=150

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Solve x+8y/4=9y for x
nikklg [1K]

Answer:

x = 7y

Step-by-step explanation:

x+8y/4=9y

Multiply each side by 4 to get rid of the fractions

4(x+8y/4)=9y*4

Distribute

4x +8y = 36y

Subtract 8y from each side

4x +8y-8y = 36y-8y

4x = 28y

Divide each side by 4

4x/4 = 28y/4

x = 7y

6 0
3 years ago
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The sum of nine times a number and five is one hundred eighty-five
tangare [24]

Answer:

9 x (x +5) = 185

Step-by-step explanation:

I'm pretty sure this is how you write it

4 0
3 years ago
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9) Nancy starts a race at the start line and she is running 3 meters per second. Juan starts the same race 3 meters ahead of Nan
Travka [436]

Given:

Nancy is running 3 meters per second.

Juan starts the same race 3 meters ahead of Nancy but he is going at 2 meters per second.

To find:

The equations for Nancy and Juan.

Solution:

Let x be the number of seconds.

Nancy is running 3 meters per second. So, the total distance covered by Nancy in the race is

y=3x

Juan starts the same race 3 meters ahead of Nancy but he is going at 2 meters per second. So, the total distance covered by Juan in the race is

y=3+2x

Therefore, the equations of Nancy and Juan are y=3x and y=3+2x respectively.

5 0
3 years ago
The rise and span for a roof are shown The pitch of a roof is the ratio of the rise to the half-span. If the rise is 8 ft and th
Amiraneli [1.4K]
The pitch in simplest form is 4/15
8 0
3 years ago
n automatic machine in a manufacturing process is operating properly if the lengths of an important subcomponent are normally di
Paraphin [41]

Answer:

0.3557 = 35.57% probability that one selected subcomponent is longer than 118 cm.

Step-by-step explanation:

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Normally distributed with a mean of 116 cm and a standard deviation of 5.4 cm.

This means that \mu = 116, \sigma = 5.4

Find the probability that one selected subcomponent is longer than 118 cm.

This is 1 subtracted by the pvalue of Z when X = 118. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{118 - 116}{5.4}

Z = 0.37

Z = 0.37 has a pvalue of 0.6443

1 - 0.6443 = 0.3557

0.3557 = 35.57% probability that one selected subcomponent is longer than 118 cm.

8 0
3 years ago
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